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1 year ago

8

An astronaut who weighed 150 pounds on earth found that his weight on jupiter was 400 pounds. he captured an alien that weighed

120 pounds on jupiter. what is the alien's weight on earth? a. 45 pounds c. 500 pounds b. 30 pounds d. 320 pounds

1 answer:

Grace [21]1 year ago

5 0

(120*150)/400 =45 lbs

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Help #2-8 please thank you !

lapo4ka [179]

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3. $1.65
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3 years ago

ILL MAKE BRAINLY??!!!?!!!!!

Leno4ka [110]

Answer:

Mizuki here to answer! B is the correct answer!

Step-by-step explanation:

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2 years ago

Each week, Alfonso earns $85 for every shift he works at the theater and $15 for every dog-walking job. He uses the expression 8

sesenic [268]

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3 years ago

Gwar [14]

Answer:

LINE D

Step-by-step explanation:

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3 years ago

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

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3 years ago