Answer:
y+4=-36 and the answer is y=-40
Step-by-step explanation:
So the word is means equals, meaning we can change it to say
"y more than 4 = -36
and more than means addition so we can put a plus sign there and we get
y+4=-36
then to solve this equation we need to get y by itself on one side and to do that we can move the 4 to the other side by subtracting it on both sides to cancel out the addition and we get y=-40
I hope this helps and please don't hesitate to ask if there is anything still unclear!
Y = - 5 x + 10
A ) x = - 15, y = 5
5 = 75 + 10
5 ≠ 85
B ) x = 2, y = 0
0 = - 5 · 2 + 10
0 = 0 ( correct )
C ) x = - 1, y = - 5,
- 5 = 5 + 10
- 5 ≠ 15
D ) x = 3, y = 25
25 = - 15 + 10
25 ≠ - 5
Answer:
B ) ( 2, 0 )
What how is this a problem and how are you in middle school
Answer:
(c)
Step-by-step explanation:
3+2+4 = 9, 4+2= 6- 3= 3
Answer:
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Step-by-step explanation:
solving for dy/dx
multiply the equation out to remove parentheses

now differentiating in terms of x (
)
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isolating dy/dx to one side


