Step-by-step explanation:
![\longrightarrow \rm{{\Bigg ( \dfrac{a}{b} \Bigg )}^c} \\ \\ \longrightarrow \rm{{\Bigg ( \dfrac{2}{3} \Bigg )}^5} \\ \\ \qquad \qquad \bigstar \: \boxed{ \bf{ \Bigg ({\frac{x}{y} \Bigg )}^{m} = \frac{ {x}^{m} }{ {y}^{m}} }} \\ \\ \longrightarrow \rm{ \frac{ {(2)}^{5} }{ {(3)}^{5} } } \\ \\ \longrightarrow \bf{ \frac{ 32 }{ 243} }](https://tex.z-dn.net/?f=%20%5Clongrightarrow%20%5Crm%7B%7B%5CBigg%20%28%20%5Cdfrac%7Ba%7D%7Bb%7D%20%5CBigg%20%29%7D%5Ec%7D%20%5C%5C%20%20%5C%5C%20%20%5Clongrightarrow%20%5Crm%7B%7B%5CBigg%20%28%20%5Cdfrac%7B2%7D%7B3%7D%20%5CBigg%20%29%7D%5E5%7D%20%20%5C%5C%20%20%5C%5C%20%20%20%5Cqquad%20%5Cqquad%20%5Cbigstar%20%5C%3A%20%5Cboxed%7B%20%5Cbf%7B%20%20%5CBigg%20%28%7B%5Cfrac%7Bx%7D%7By%7D%20%5CBigg%20%29%7D%5E%7Bm%7D%20%20%3D%20%20%5Cfrac%7B%20%7Bx%7D%5E%7Bm%7D%20%7D%7B%20%7By%7D%5E%7Bm%7D%7D%20%20%20%7D%7D%20%5C%5C%20%20%5C%5C%20%20%5Clongrightarrow%20%5Crm%7B%20%5Cfrac%7B%20%7B%282%29%7D%5E%7B5%7D%20%7D%7B%20%7B%283%29%7D%5E%7B5%7D%20%7D%20%7D%20%5C%5C%20%20%5C%5C%20%5Clongrightarrow%20%20%5Cbf%7B%20%5Cfrac%7B%2032%20%7D%7B%20243%7D%20%7D%20)
Therefore, 32/243 is the answer.
The probability of landing a 6 with a six sided die is 1/6
Answer:
There is an infinite number of lines that pass through the point (2, 11). Therefore, there is an infinite number of equations. To define a single line, you must have at least two points. One point is not enough.