What the square root 11?

Angles of triangle sand explain how u got each question and answer pls ! ((:

horsena [70]

Answer:

m∠1 = 41°

m∠2 = 85°

m∠3 = 95°

m∠4 = 85°

m∠5 = 36°

m∠6 = 49°

m∠7 = 96°

Step-by-step explanation:

Alright, so to start we have 2 quadrilaterals intersecting to form a triangle, which means that in the shapes with 4 angles, all angles will add up to 360°, while the triangle's angles will add up to 180°

Right off the bat, we can tell that ∠3 and ∠95° are going to be the same, because they're at a perpendicular intersection, which also means that ∠2 and ∠4 will be the same as well

Knowing the ∠3 = 95° means that ∠5 and ∠6 must add up to equal 85°, so that the whole of the triangle equals 180°

Considering that in the first quadrilateral we already have ∠90° and ∠144°, this means that ∠1 and ∠2 have to add up to 126°, to make an even 360° total

If ∠95° is supplementary to ∠2, this means ∠2 = 85°, and since ∠4 and ∠2 are the same, ∠4 also equals 85° - This leaves 41° left for ∠1, and now we can move on to the other quadrilateral

So since we know ∠4 = 85°, and we already have ∠38°, this means that ∠7 and the unmarked angle will add up to equal 237°, so that the entire shape has 360°

Since we know that ∠5 and ∠144° are supplementary, this means ∠5 is equal to 36°, which would make ∠6 = 39°

And lastly we have ∠7, which since ∠6 = 39° this means our unmarked supplementary angle must equal 141° - Now that means that ∠4 + ∠38° + ∠141° = 264° out of 360°, which leaves ∠7 to equal 96°

3 0

3 years ago

Evaluate the limit with either L'Hôpital's rule or previously learned methods.lim Sin(x)- Tan(x)/ x^3x → 0

Vsevolod [243]

Answer:

$\dfrac{-1}{6}$

Step-by-step explanation:

Given the limit of a function expressed as $\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}$ , to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

$= \dfrac{sin(0)-tan(0)}{0^3}\\= \frac{0}{0} (indeterminate)$

Step 2: Apply L'Hôpital's rule, by differentiating the numerator and denominator of the function

$= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\$

Step 3: substitute x = 0 into the resulting function

$= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)$

Step 4: Apply L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

$= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\$

$= \dfrac{-sin(0)-2sec^2(0)tan(0)}{6(0)}\\= \frac{0}{0} (ind)$

Step 6: Apply L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

$= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\$

Step 7: substitute x = 0 into the resulting function in step 6

$= \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}$

<em>Hence the limit of the function </em> $\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \ is \ \dfrac{-1}{6}$ .

3 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIST

shtirl [24]

The minimum is 91. The first quartile is 112. The median is 173. The third quartile is 215. The maximum is 253.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%3D-2%5C%5Cx%2B3y%3D4" id="TexFormula1" title="x=-2\\x+3y=4" alt="x=-2\\x+3y=4" align="absmid

Natali5045456 [20]

X + 3y -4 =0 or x=4 I think that’s the answer

4 0

2 years ago

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5%

vladimir1956 [14]

Complete Question

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5% for 3 years

Answer:

$ 12,934.61

Step-by-step explanation:

The formula for Compound Interest Compounded continuously is given as:

A = Pe^rt

A = Amount after t years

r = Interest rate = 2.5%

t = Time after t years = 3

P = Principal = Initial amount invested = $12,000

First, convert R percent to r a decimal

r = R/100

r = 2.5%/100

r = 0.025 per year,

Then, solve our equation for A

A = Pe^rt

A = 12,000 × e^(0.025 × 3)

A = $ 12,934.61

The total amount from compound interest on an original principal of $12,000.00 at a rate of 2.5% per year compounded continuously over 3 years is $ 12,934.61.

7 0

2 years ago