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azamat
3 years ago
13

If after several rounds of artificial selection all alleles affecting the trait are fixed or lost, the narrow-sense heritability

(h^{2}) of a trait is
Biology
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

h^2 = 0

Explanation:

When trait variance is a result of additive genetic factors, it is referred to as 'narrow sense heritability' or h^2. This estimate falls within a range of 0 to 1. h^2 is significant in indicating the evolutionary potential of a certain trait under study. Heritability value close to zero means that the variation in that trait is predominantly a result of environmental factors.

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yanalaym [24]
Exactly 989527/1048576, or approximately 94.37%  
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB 
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So 
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%  
So the answer is exactly 989527/1048576, or approximately 94.37%
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