Let's take a look at the equation.
×
Now, all you would have to do is solve it.
×
=
(can't be reduced any further)
Your answer would be .
I hope this helps!
Answer:
{ N+11 }x5
Step-by-step explanation: First you have to add <n> plus eleven. In order to get a sum, you must multiply by five.
Answer:
(x + + )(x + - )
Step-by-step explanation:
solve the polynomial for x then express in product of factor form
Solve
x² + x - 10 = 0 ( add 10 to both sides )
x² + x = 10
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2( )x + = 10 +
(x + )² = ( take the square root of both sides )
x + = ± = ± ( subtract from both sides )
x = - ±
Thus corresponding factors are
(x - (- - ) ) and (x - (- + ), that is
(x + + ) and ( x + - )
Thus
x² + x - 10 = ( x + + )(x + - ) ← in factored form
Answer:
y-intercept = 0, slope = 4
The complete question is
"which statement is true about the extreme value the given quadratic equation? y = -3x^2 + 12x - 33
Oa. The equation has a maximum value with a y coordinate of -27
Ob. The equation has a minimum value with a y coordinate of -21
Oc. the equation has a minimum value with a y coordinate of -27
Od. The equation has a maximum value with a y coordinate of -21"
The quadratic equation has the extreme value at the vertex with a y-coordinate of -21. so, the correct option is D.
<h3>What is a quadratic equation?</h3>
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
The given quadratic equation is
y=-3x^2+12x-33
x = -b/2a
For the given equation the vertex :
x = -12/2(-3) = 2
The value of y at x = 2 is:
y = -3(2²) + 12(2) - 33
y = -12 + 24 - 33
y = -21
The extreme is the maximum for the given equation.
The correct choice is D.
Learn more about quadratic equations;
brainly.com/question/13197897
#SPJ1