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3 years ago

Explain 3 types of lubrication occurs in bearings?

Engineering

1 answer:

Angelina_Jolie [31]3 years ago

8 0

Answer:

The three types of lubrication occurred in the bearing are:

When the lubrication occur in the bearing it play an important role in the rolling life of bearing element. Basically, lubricant task is to reduced the friction.

1) Grease lubricant: Grease contain various type of additives which help in enhance the performance. It consist of oil where thickness are added as, this thickness improved the characteristics of grease.

2) Oil lubricant: This is used to reduced or minimized the friction and the lubricant oil is used to in those vehicles when they are motorized. Bearing lubricant oil is used to higher the speed capability.

3) Solid films: These are non fluid coating surface that are applied in the friction surface for prevention. It is used in very extreme situation where oil and grease types of lubricant does not work.

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Use a passband of 0 to 5 kHz with 5 kHz cutoff frequency and filter to attenuate all frequencies at and above 10 kHz by at least

Alinara [238K]

Answer:

See attached picture for answer.

Explanation:

See attached picture for explanation.

5 0

3 years ago

Your new mobile phone business is now approaching its first anniversary and you are able to step back and finally take a deep br

Leya [2.2K]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

7 0

3 years ago

Why some types of aggregate are susceptible to damage from repeated freezing and thawing? Explain.

koban [17]

Answer:

Some types of aggregate are susceptible to damage from repeated freezing and thawing due to their porosity. An aggregate being porous allows water molecules to enter in between the rocks.

When freezing occurs, water is known to expand. The expansion of this in the rocks creates a type of pressure which results in the fracture of the rocks. Subsequent freezing and thawing will allow for more fracture between the rock particles which will lead to its disintegration.

8 0

4 years ago

Assume we have already defined a variable of type String called password with the following line of code: password' can have any

omeli [17]

Answer:

The Java code is given below with appropriate comments for better understanding

Explanation:

import java.util.Scanner;

public class ValidatePassword {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print("Enter a password: ");

String password = input.nextLine();

int count = chkPswd(password);

if (count >= 3)

System.out.println("Secure");

else

System.out.println("Not Secure");

}

public static int chkPswd(String pwd) {

int count = 0;

if (checkForSpecial(pwd))

count++;

if (checkForUpperCasae(pwd))

count++;

if (checkForLowerCasae(pwd))

count++;

if (checkForDigit(pwd))

count++;

return count;

}

// checks if password has 8 characters

public static boolean checkCharCount(String pwd) {

return pwd.length() >= 7;

}

// checks if password has checkForUpperCasae

public static boolean checkForUpperCasae(String pwd) {

for (int i = 0; i < pwd.length(); i++)

if (Character.isLetter(pwd.charAt(i)) && Character.isUpperCase(pwd.charAt(i)))

return true;

return false;

}

public static boolean checkForLowerCasae(String pwd) {

for (int i = 0; i < pwd.length(); i++)

if (Character.isLetter(pwd.charAt(i)) && Character.isLowerCase(pwd.charAt(i)))

return true;

return false;

}

// checks if password contains digit

public static boolean checkForDigit(String pwd) {

for (int i = 0; i < pwd.length(); i++)

if (Character.isDigit(pwd.charAt(i)))

return true;

return false;

}

// checks if password has special char

public static boolean checkForSpecial(String pwd) {

String spl = "[email protected]#$%^&*(";

for (int i = 0; i < pwd.length(); i++)

if (spl.contains(pwd.charAt(i) + ""))

return true;

return false;

}

5 0

3 years ago

A 2 m3 insulated rigid tank contains 3 kg of nitrogen at 90 kPa. Now work is done on the system until the pressure in the tank r

Nutka1998 [239]

Answer: $\Delta S$ = 1.47kJ/K

Explanation: Entropy is the measure of a system's molecular disorder, i.e, the unuseful work a system does.

The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.

For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:

$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}$

$\frac{P_{2}}{P_{1}} =\frac{T_{2}}{T_{1}}$

$\frac{T_{2}}{T_{1}} =\frac{175}{90}$

$\frac{T_{2}}{T_{1}} =1.94$

Specific Heat is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is $c_{v}=$ 0.743kJ/kg.K