Answer:
the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Explanation:
Given that;
depth 1 = 71 ft
depth 2 = 10 ft
pressure p = 17 psi = 2448 lb/ft²
depth h = 71 ft - 10 ft = 61 ft
we know that;
p = P_air + yh
where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )
so we substitute;
p = 2448 + ( 49.3 × 61 )
= 2448 + 3007.3
= 5455.3 lb/ft³
= 37.88 psi
Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Ram is the better truck company
Answer:
potato<-100
print(potato)
sqrt(potato)
potato<-potato*2
print(potato)
Explanation:
The complete question is as follows
Create a variable called potato whose value corresponds to the number of potatoes you’ve eaten in the last week. Or something equally ridiculous. Print out the value of potato.
Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value of potato hasn’t changed.
Reassign the value of potato to potato * 2.
Print out the new value of potato to verify that it has changed
The question was answered using R programming language.
At line 1, I assumed that I ate 100 potatoes in the previous week.
So, potato = 100
At line 2, the value of potato is printed as 100.
At line 3, the square root of potato is calculated using sqrt function: Square for of 100 = 10
At line 4,the initial value of potato is doubled and stored in potato variable. 100 * 2 = 200
At line 5, the new value of potato is printed: 200.
Answer:
You're answer would be "D. Perform all of the above"
Explanation:
Have a Blessed Day (Mark Brainliest!)
Answer:
I think
when the problem has numerous possible options.
If wrong correct me pls
<em><u>Have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em>
<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em>
<em><u>
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