All categories

3 years ago

What type of line shows transition?

Engineering

2 answers:

Vika [28.1K]3 years ago

6 0

Shutup give me the points .

Marina CMI [18]3 years ago

3 0

Straight lines show the conversion between a photon of light and the energy of an electron. Curved lines show transitions of electrons without any interaction with light.

You might be interested in

Rank the magnitudes of the diffusion coefficients from greatest to least for the following systems:(a) Cr in Fe at 600°C; (b) C

jek_recluse [69]

Answer:

Explanation:

The rank of the magnitude of the diffusion coefficient from greatest to least is as follows:

C in Fe at 900°C > Cr in Fe at 900°C > Cr in Fe at 600°C

Reason

C in Fe is an interstitial impurity while Cr in Fe is a substutional impurity.Therefore interstitial impurity occurs in C in Fe systems,while substutitional diffusion occurs in Cr in Fe system.Interstitial is much faster than substitutional diffusion hence the order

Also with increasing temperature magnitude of diffusion coefficient increases,due to the relation.

D = D₀exp(-Qd/RT)

Where D₀=Temperature independent per exponential

Qd= The activation energy for diffusion

R= Universal gas constant

T=absolute temperature

3 0

3 years ago

Read 2 more answers

A heat engine uses fuel of energy content 43.1 MJ/kg and produces 17.4 kW of useful power. The heat rejection rate (through the

solmaris [256]

Answer:

a)27.9%

b) $\dot{m}=3.06 \frac{Kg}{h}$

Explanation:

Given that

Fuel energy content = 73.1 MJ/kg

Useful power = 17.4 KW

Heat rejection rate = 44.8 KW

From first law of thermodynamics

Heat addition rate =Heat rejection rate + Power out put

Now by putting the values in the above formula

Heat addition rate = 44.8 + 17.4

Heat addition rate =62.2 KW

We know that efficiency is given as follows

$\eta =\dfrac{power\ out\ put}{Heat\ addition\ rate}$

$\eta =\dfrac{17.4}{62.2}$

$\eta =0.279$

So the efficiency is 27.9%.

Now to find usage rate of fuel

Lets take usage rate is $\dot{m}$

Fuel energy content x usage rate of fuel = Heat addition rate

Now by putting the values

$73100\times \dfrac{\dot{m}}{3600}=62.2$

$\dot{m}=3.06 \frac{Kg}{h}$

7 0

3 years ago

Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid–vapor mixture region using 1.06 kg of

Alexxandr [17]

Answer:

$P_m_i_n = 442KPA$

Explanation:

We are given:

m = 1.06Kg

$T_H = 1.2T_L$

T = 22kj

Therefore we need to find coefficient performance or the cycle

$COP_R = \frac {1}{(T_R/T_l) -1}$

$= \frac {1 }{1.2-1}$

= 5

For the amount of heat absorbed:

$Q_l = COP_R Wm$

= 5 × 22 = 110KJ

For the amount of heat rejected:

$Q_H = Q_L + W_m$

= 110 + 22 = 132KJ

[tex[ q_H = \frac{Q_L}{m} [/tex];

= $= \frac{132}{1.06}$

= 124.5KJ

Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c

Convert 69.5°c to K we have 342.5K

To find the minimum temperature:

$T_L = \frac{T_H}{1.2}$ ;

$T_L = \frac{342.5}{1.2}$

= 285.4K

Convert to °C we have 12.4°C

From the refrigerant R -134a table at $T_L$ = 12.4°c we have 442KPa

6 0

3 years ago

Air flows steadily through a smooth, converging nozzle. At a location where the cross-sectional flow area is equal to 1.0 ft2, t

mote1985 [20]

Answer:

match number at location 1 = 0.197

velocity at location1 =

velocity at location 2 = 356.56 fhz

match number at location 2 = 0.282

Explanation:

check the attachment for the solution

8 0

4 years ago

Read 2 more answers

Sam, a carpenter, is asked to identify the abilities he has that are important to his work. What are the top abilities he might

Sergeeva-Olga [200]

Answer

visualization, problem sensitivity, and manual dexterity

Explanation

6 0

3 years ago

Read 2 more answers