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3 years ago

9

Please help I can’t solve this

1 answer:

Vika [28.1K]3 years ago

5 0

1.25

If you take the difference between two y axis numbers (say 5 and 10) which is 5 and the difference between two X axis numbers (say 4 and 8) which is 4. The y axis is the rise(5) and the x axis is the run(4). Using the formula rise/run (5/4) you can calculate the answer to be 1.25.

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Find the value of tan(sin^-1(1/2))

suter [353]

If you know that $\sin\dfrac\pi3=\dfrac12$ , then you know right away

$\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3$

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

So, recalling the Pythagorean theorem, we find

$\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2$

Then

$\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3$

as expected.

5 0

3 years ago

Read 2 more answers

Factorise:<br> 8 x 3 + 729 +10800² + 486X.

hjlf

Answer:

(2x+9) ^3

Step-by-step explanation:

(((8 • (x3)) + 729) + (22•33x2)) + 486x

((23x3 + 729) + (22•33x2)) + 486x

Factoring: 8x3+108x2+486x+729

8x3+108x2+486x+729 is a perfect cube which means it is the cube of another polynomial

In our case, the cubic root of 8x3+108x2+486x+729 is 2x+9

Factorization is (2x+9)3

Hope this helped

8 0

3 years ago

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Simplify the expression 8x^-4 y^-8/-2xy^5 (Note ^ equals to the power of)

krek1111 [17]

-4/x^5y^13 because since you have negative exponents on the top you switch them to the bottom

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3 years ago

Jonah has a large collection of marbles he notices that if he borrows five marbles from a from a friend he can arrange the marbl

olga nikolaevna [1]

Answer:

The remainder is 8

Step-by-step explanation:

Let Jonah's Marble=x

If he arranges x marbles into y rows of 13 each, and there are remainders(R)

Then:

x/13=y+(R/13).....(I)

If he borrows 5 marbles from a friend, there will be no remainder. However, the number of rows y, will be increased by 1

New Total Marbles=x+5

(x+5)/13=y+1.....(ii)

x+5=13(y+1)

x=13y+13-5

x=13y+8

From (I)

x=13y+R

Comparing the values of x derived from (I) and (ii)

13y+R=13y+8

Therefore the Remainder, R= 8

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4 years ago

Given the formula C= 1/2t(c1-c2), solve for t.

kobusy [5.1K]

Answer:

$t=\frac{2C}{c1-c2}$

Step-by-step explanation:

$C=\frac{1}{2}t(c1-c2)\\2(C)=2(\frac{1}{2}t(c1-c2))\\2C=t(c1-c2)\\\frac{2C}{c1-c2}=\frac{t(c1-c2)}{c1-c2}\\t=\frac{2C}{c1-c2}$

3 0

3 years ago

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