Question

Jenna has a bag that contains 7 red marbles and 25 blue marbles. She selects a marble at random, and then, without replacing the first one, selects another marble at random.
 
What is the probability that Jenna selects a blue marble and then a red marble? Round your answer to the nearest percent.
 

Answer 1

I think the answer is somewhere above 50%

Answer 2

Probability to get a blue marble first = $\frac{25}{25+7} = \frac{25}{32}$

Probability of getting a red marble next = $\frac{7}{32-1} = \frac{7}{31}$

Total probability = $\frac{25}{32}* \frac{7}{31} = \frac{175}{992}$

Percentage probability = $\frac{175}{992} *100= 17.6$