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3 years ago

Which best explains what determines whether a number is irrational?

2 answers:

7 0

Is it squared rationally?
Is it a repeating decimal?

Every /non/-repeating decimal is irrational, as well all fractions.

If you have anymore questions go to algebra.com.

rusak2 [61]3 years ago

6 0

<span>1.) Is 64 squared rational or irrational?
Ans: Rational
----------------
2.) Is -1.2 repeating decimal rational or irrational?
Every repeating decimal is rational.
Every non-repeating decimal is irrational.
All whole numbers are rational.
All fractions are rational.
nth roots of a^k are irrational unless k is a multiply of n.
Example: The cube root of 3^6 is rational but the cube root of 3^5 is not.
Cheers,
Stan H. </span>

You might be interested in

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Istg if yall put any links-

Naddik [55]

Answer:

Step-by-step explanation:

7 0

3 years ago

Solve this math problem -2 1/3-(-5)=

dmitriy555 [2]

Answer:

8/3 or 2.6 repeating

4 0

3 years ago

Read 2 more answers

The solid surface area is equal to the solid volume. Find the value of x? The measurements of the rectangular prism is 9 inches

Fudgin [204]

Answer:

$x=7.2$

Step-by-step explanation:

Let x represent height of the prism.

We know that volume of rectangular is equal to product of its height, width and length.

$\text{Surface area of rectangular prism}=2(wl+lh+hw)$ , where w, h and l represents width, length and height respectively.

We have been given that the surface area of rectangular prism is equal to the volume of the prism. So we can set an equation as:

$lwh=2(wl+lh+hw)$

We are also told that the measurements of the rectangular prism is 9 inches long and 4 inches wide. Upon substituting these values in above equation, we will get:

$9\cdot 4\cdot x=2(4\cdot 9+9\cdot x+x\cdot 4)$