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iragen [17]
3 years ago
5

A rectangular storage container with an open top is to have a volume of 10 m3. The length of this base is twice the width. Mater

ial for the base costs $15 per square meter. Material for the sides costs $9 per square meter. Find the cost of materials for the cheapest such container. (Round your answer to the nearest cent.)
Mathematics
1 answer:
Gala2k [10]3 years ago
8 0
L = 2 W
B = L x W = 2 W²
Side Area = 2 W H + 2 L H = 2 H ( W + L ) = 6 H W
V = 2 W² H = 10
H = 5 / W²
Cost = 15 * 2 W² + 9 * 5/W
= 30 W² + 270/ W 
C ` = 60 W - 270 / W² 
= ( 60 W² - 270 ) / W² = 0
60 W² = 270
W ² = 270 : 60
W² = 4.5
W = √ 4.5 = 2.12
Cost (min) = 15 * 2 * 4.5 + 30 / 2.12 = 135 + 14.15 = $149.15
Answer: The cost of materials for the cheapest such container is $149.15. 
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The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
13(10 + 2) could be used to simplify which of the following problems?
Veseljchak [2.6K]
Well first you need to show the rest of the problems before i can truely help you sorry.
6 0
3 years ago
At a regional soccer​ tournament, tickets for two adults and seven students cost ​$60. Tickets for three adults and eleven stude
den301095 [7]

Answer:

The price of an adult ticket is $9 and the price of a student ticket is $6

Step-by-step explanation:

Create a system of equations where x is the price of an adult ticket and y is the price of a student ticket:

2x + 7y = 60

3x + 11y = 93

Solve by elimination by multiplying the top equation by 3 and the bottom equation by -2, to cancel out the x terms:

6x + 21y = 180

-6x - 22y = -186

Add them together:

-y = -6

y = 6

Then, plug in 6 as y into one of the equations to solve for x:

2x + 7y = 60

2x + 7(6) = 60

2x + 42 = 60

2x = 18

x = 9

So, the price of an adult ticket is $9 and the price of a student ticket is $6

8 0
3 years ago
Answer choices: (5,6) (5,2) (3,6) (3,2).
Degger [83]

Answer:

(3,6)

Step-by-step explanation:

If the starting point is the dot then we start from there - (4,4) then we go up 2 units at (4,6) then moving one unit to the left our answer is (3,6).

6 0
3 years ago
What is the area of this figure?<br><br> A.49.5 in²<br> B.66.5 in²<br> C.84 in²<br> D.91 in²
aliya0001 [1]
The area of a trapezoid with base lengths 7 in and 19 in is given by
  A = (1/2)(b1 + b2)h
  A = (1/2)(7 +19)·7 = 91

The appropriate choice is
  D. 91 in²


_____
It can also be figured by adding the area of the 7 in square (49 in²) to the area of the 7×12 in right triangle (42 in²).
3 0
3 years ago
Read 2 more answers
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