The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532
Answer:
Follow the steps I did in the explanation.
Step-by-step explanation:
It says to evaluate the equation :-
3.2 = 4/5(b - 5)
3.2 = (4/5 × b) + (4/5 × -5)
3.2 = 4/5b - 4
3.2 + 4 = 4/5b
5/4 × 7.2 = b
9 = b
Hope this helps, thank you :) !!
Answer:
7cm
14cm
dπ or 2r π
14π or 2(7π)
Step-by-step explanation:
Radius = 7cm
Diameter = 7 x 2 = 14cm
Circumference = 2 x π x r = dπ
Circumference Value = 2 x π x 7 = 14π
5x’2-4x+7-4x-2
We add the two 4
5x’2-8x+7-2
5x’2-8x+5
The answer is
5x’2 -8x +5
