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frez [133]
3 years ago
10

The dartboard represented below has 3 circular areas with point values of 10, 6, and 4 points. The radii of the circles are 3 in

ches, 6 inches, and 9 inches. Which is closest to the area of the region that is worth 4 points?
226 in.^2
63 in.^2
113 in^2
141 in.^2
Please! If you could at least find the formula to do this problem that would be great.

Mathematics
2 answers:
Kitty [74]3 years ago
6 0

Answer:

141 in²

Step-by-step explanation:

Outer circle - middle circle

3.14 × (9² - 6²)

3.14 × 45

141.3 in²

Zinaida [17]3 years ago
4 0

Answer:

141 in.^2

Step-by-step explanation:

First find the area of the full circle

The radii is 9 inches

A = pi r^2

A = 81 pi

Then find the area of the  next smallest circle which is 6 inches

A = pi r^2

A = 36 pi

Subtract the difference to get the area of the blue

81pi - 36 pi

45 pi

45 * 3.14

141.3

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the end of the road is 15/16 of a mile away. Luke walked 7/8 of a mile down the road. How much further did he need to walk
AURORKA [14]

Answer:

1/16 of a mile left to walk to reach the end of the road

Step-by-step explanation:

The total distance to be walked = 15/16 miles

already walked= 7/8 miles = 14/16 miles

15/16 - 14/16 = 1/16 miles

4 0
2 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^(2)+4x-5=3x+2
krek1111 [17]
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
4 0
2 years ago
What is the square root of 12 in radical form?
Molodets [167]

Answer:

2√3 is the simplest radical form.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
4x-1 + 2x-1 = 5x how do I solve this problem?
GREYUIT [131]

Answer: 2=x

Step-by-step explanation:

4x-1 + 2x-1 = 5x

First combine like terms together

4x-1 + 2x-1 is 4x+2x-1-1

4x+2x-1-1 =6x-2

4x-1 + 2x-1=6x-2

6x-2=5x

The oppisite of 6x is -6x so -6x on both sides of equation to keep it balanced

6x-6x-2=5x-6x

0-2=-1x

-2=-1x

Divide both sides of the equation by -1 since -1 is being multiplied by x and the oppisite of multiply is divide

-2/-1=-1x=-1

2=x

6 0
3 years ago
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