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stira [4]
3 years ago
9

Use Pascal’s triangle and binomial expansion strategies (x+y)^3

Mathematics
1 answer:
mariarad [96]3 years ago
3 0
<h2>1. Pascal’s triangle</h2>

Pascal's triangle is an strategy in math that stands for a triangular array we use to solve problems of binomial coefficients. This strategy is called after the mathematician Blase Pascal. It consists in number patters. So in this problem we need to solve this following Pascal’s triangle strategy:

(x+y)^3

The strategy consists in building a triangle. So 1 is the first and last numbers in each row of Pascal’s Triangle. Next, every other  number in each row is formed when you add the two numbers directly above the  number, as shown in Figure below. So:

(x+y)^3=x^3+3x^2y+3xy^2+y^3

<h2>1. Binomial Expansion</h2>

A binomial is a polynomial having two terms. So binomial expansion is a method that stands for a formula that gives us a quick method of raising a binomial to a power. So, for n=3, the binomial expansion can be written as:

(x+y)^3=x^3+3x^2y+3xy^2+y^3

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see the attached figure

 

the answer is

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5 0
3 years ago
Which of the following equations have the same solution? Give reasons for your answer that do not depend on solving the equation
KATRIN_1 [288]

Answer:

none

Step-by-step explanation:

A. -7+4x=9  4x=9+7 x=4

B.  x= -1

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E. x =  -12

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7 0
4 years ago
Read 2 more answers
Which choices are real numbers? Check all that apply. (-22)½ (-16)⅓ (-16)⅕ (-10)¼
8_murik_8 [283]

(-22)^{\frac{1}{2}} and (-10)^{\frac{1}{4}} are not real numbers

<h3><u>Solution:</u></h3>

A real number is any positive or negative number. This includes all integers and all rational and irrational numbers

They are called "Real Numbers" because they are not Imaginary Numbers.

When you take an even root of a negative number, there is no real answer. (2 is an even number)

In the real number set, you can't take an even-indexed root of a negative number.

Given options are:

\begin{array}{l}{\text { A) }(-22)^{\frac{1}{2}}} \\\\ {\text { B) }(-16)^{\frac{1}{3}}} \\\\ {\text { C) }(-16)^{\frac{1}{5}}} \\\\ {\text { D) }(-10)^{\frac{1}{4}}}\end{array}

Looking at the answer choices here, we can see that A and D use even roots, so they will give non-real answers.

Thus (-22)^{\frac{1}{2}} and (-10)^{\frac{1}{4}} are not real numbers

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3 years ago
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4 0
3 years ago
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irina [24]

Answer:

Is there a full question??

Step-by-step explanation:

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