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Marysya12 [62]
3 years ago
6

Which statements are true?

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0

Answer:

The first one and the last one are true (Since −6 is 6 units to the left of 0, |−6|=6 and −6 is closer to zero on the number line than −7, so |−6|<|−7|.)

Step-by-step explanation:

Absolute value is the distance to zero, and it is always positive. That means the positive and negative versions of a number have the same absolute value. That means the first one is true, and the second and third ones are false. For the last one, -6 is closer to zero, so that means it would be true (The absolute value of -6 is 6, and the absolute value of -7 is 7).

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Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

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Step-by-step explanation:

no

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