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2 years ago

Please help I'm desperate...

Mathematics

1 answer:

Evgen [1.6K]2 years ago

6 0

Ok here’s the answer! I again had to crop out the first step. here it was to divide equation 1 by 3 and add that to equation 2. all you need do you show that step is to write equation 1: -3x+2y=8 and equation 2: (11y/3)=35/3

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2x+2(1960/x)=200 please help for math hw

sp2606 [1]

Two solutions:

1. x =(100-√2160)/2=50-6√ 15 = 26.762

2. x =(100+√2160)/2=50+6√ 15 = 73.238

3 0

3 years ago

The sales tax on a $24 model rocket is $1.92 what is the percent of sales tax

AleksAgata [21]

Input data

Price model rocket = $24

Tax = $1.92

What is the percent of sales tax?

Procedure

r = percent of sales tax

$r=\frac{1.92}{24}=0.08=8\text{ \%}$

The answer would be 8%

8 0

10 months ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

A sphere has a diameter of 10 in. What is the volume of the sphere?

givi [52]

The volume of sphere is $\frac{500}{3}\pi$ inches cubed.

Step-by-step explanation:

Given,

Diameter of sphere = 10 inches

Radius of sphere = $\frac{Diameter}{2}=\frac{10}{2}$

Radius of sphere = 5 inches

Volume of sphere = $\frac{4}{3}\pi r^3$

V = $\frac{4}{3}\pi (5)^3$

$V = \frac{4}{3}\pi * 125\\\\V = \frac{500}{3}\pi$

The volume of sphere is $\frac{500}{3}\pi$ inches cubed.

Keywords: volume, division

Learn more about division at:

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

(Smallest to Largest) 1.8 , 0.8 , 8 , 8.1

Natasha_Volkova [10]

.8, 1.8, 8, 8.1

Do you understand why? This seems pretty simple that you should be able to solve this for yourself.

5 0

3 years ago