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drek231 [11]
3 years ago
12

Write 0.01 as a fraction a. 1 1/10 b. 1/10 c. 1/100 d. 1

Mathematics
2 answers:
Vikki [24]3 years ago
8 0

I think it c.1/100 because it has two zero .

 

Lady_Fox [76]3 years ago
5 0
C. 01/100.    .01 is in the hundredths place. So you put 2 0's on the denominator.
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One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit
Rasek [7]

We are given

N=\frac{11}{60} (F-32)

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

60\times N=60\times \frac{11}{60} (F-32)

60N=11 (F-32)

step-2:

Divide both sides by 11

\frac{60N}{11} =\frac{11(F-32)}{11}

\frac{60}{11}N =F-32

step-3:

Add both sides by 32

\frac{60}{11}N+32 =F-32+32

\frac{60}{11}N+32 =F

so, we get

F=\frac{60}{11}N+32................Answer

5 0
3 years ago
Is the square root of eight a rational or irrational number
shutvik [7]
\bf \sqrt{8}\implies \sqrt{2\cdot 2\cdot 2}\implies \sqrt{2^2\cdot 2}\implies 2\sqrt{2}

it just so happen that √2 is an irrational number, so any product with it as a factor, will yield an irrational number as well.



factoid:   Ancient Greeks were scared of irrational numbers, and they steered clear from √2.
8 0
3 years ago
John has purchased collision insurance with a $100-deductible clause, and automobile medical payments insurance in the amount of
Len [333]
B is answer because total of medical bill was 1,100 plus car repair cost 900 total 2,000. minus 100 dollars john has to pay for his  deductible 
4 0
3 years ago
What is the slope of the line through the points (–3, 5) and (4, 5)?
kow [346]
The answer would be zero 
5 0
3 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
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