Answer:
The distance around the inside is 199.44 m.
Step-by-step explanation:
Given that,
Length = 84.39 m
Width = 9.76 m
Suppose, all the way around and 73 m wide.
We know that,
Perimeter of half circle is
![perimeter = \pi r](https://tex.z-dn.net/?f=perimeter%20%3D%20%5Cpi%20r)
We need to calculate the inner radius of the circle
Using formula of radius
![r=\dfrac{D}{2}](https://tex.z-dn.net/?f=r%3D%5Cdfrac%7BD%7D%7B2%7D)
Put the value into the formula
![r=\dfrac{9.76}{2}](https://tex.z-dn.net/?f=r%3D%5Cdfrac%7B9.76%7D%7B2%7D)
![r=4.88\ m](https://tex.z-dn.net/?f=r%3D4.88%5C%20m)
We need to calculate the distance around the inside
Using formula of distance
Distance around the inside= two inner perimeter of the circle+two length of rectangle
![D=2\pi r+2l](https://tex.z-dn.net/?f=D%3D2%5Cpi%20r%2B2l)
Put the value into the formula
![D=2\pi\times4.88+2\times84.39](https://tex.z-dn.net/?f=D%3D2%5Cpi%5Ctimes4.88%2B2%5Ctimes84.39)
![D=199.44\ m](https://tex.z-dn.net/?f=D%3D199.44%5C%20m)
Hence, The distance around the inside is 199.44 m.
Answer:
The total cost of her lunch is $14.65
Step-by-step explanation:
15% of $12.74 is $1.91
12.74+1.91=14.65
Answer: the maximum number of guests that he can invite would be 9
Step-by-step explanation:
Darnel's retirement party cost $33, plus an additional $1 for each guest he invites. Assuming Darnel wants to invite x guests to his retirement party, the total amount of money that Darnel would spend is
33 + x
if darnel can afford to spend a total of $42 on his retirement party, then
42 = 33 + x
x = 42 - 33 = 9
LN=8 because every time there is a midpoint you have to divide it in half. So 64,32,16,8
The mean is not the same thing as median
mean=78+81+85+87=331
mean=331/4=82.75
median is the middle number, but you have a par set of numbers, so your median will be the middle numbers 78,81,85,87 , which are 81+85=166, 166/2=83
83 is your median