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Gemiola [76]
3 years ago
15

If the original quantity is 15 and the new quantity is 19, estimate the percent change.

Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

25% increase

Step-by-step explanation:

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Which graph represents a function with direct variation?<br><br>​
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This is easier than you think!

When a graph shows direct variation, it always <em>passes through the origin</em>

The origin is (0, 0)

The very <u>center! </u>

Your answer is the first graph!

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Answer:

The answer would be 7(2x+3y+z) or 7(2x+3y+1z) (both would be considered as correct)

Step-by-step explanation:


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the difference of two numbers is 16. The greater number is 5 less than 4 times the smaller number find the numbers
inna [77]
L-s=16
4s-5=l
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What is 99,999 rounded to the nearest thousands
konstantin123 [22]
100,000

is the answer 
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When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
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