SOLUTION
Set the function equal to zero to solve for x.
{
0
=
1
2
x
−
3
3
=
1
2
x
6
=
x
x
=
6
⎩
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎧
0=
2
1
x−3
3=
2
1
x
6=x
x=6
The graph crosses the x-axis at the point (6, 0).
Answer is The constant x-value is 7, so the equation is x = 7.
Answer:
a) The variable, M represents the amount of fish Ms. Montesinos has
b) The set equation is 11 + 2 = 3 × M - 2
c) 5
Step-by-step explanation:
The given parameters are;
The number of fishes in Ms. Cruz's tank = 11 fishes
The number of fishes Ms, Cruz has after buying two more fishes = 3 × The amount of fish Ms. Montesinos has - 2 fishes
a) Let the variable, M represent the amount of fish Ms. Montesinos has
b) The set up equation is as follows;
11 + 2 = 3 × M - 2
c) From the equation, 11 + 2 = 3 × M - 2, we have;
13 = 3·M - 2
3·M = 13 + 2 = 15
3·M = 15
M = 15/3 = 5
M = 5
The number of fishes Ms. Montesinos has is 17 fishes
Answer:
X cannot be decided
Step-by-step explanation:
According to the question,we will start solving the problem by dealing with the bracket first
So let's get to work
2(x-3)=2x+5
Bracket first
2x-6=2x+5
So let's collect like terms
2x-2x=5+6
0=11
Which means the that we can't get the value for x because x has already been eliminated
So to my own understanding there is no definite solution to get the real value of x
I hope you understand
Answer:
The average yearly drop in enrollment is 12.
Step-by-step explanation:
The average refers to the central value in a group of numbers and with the information provided, you can find the average by dividing the number of students that dropped out of the school by the number of years over which that ocurred:
number of students= 60
number of years= 5
60/5=12
According to this, the answer is that the average yearly drop in enrollment is 12.
