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Anastasy [175]
3 years ago
9

What does OSS mean? ??

Computers and Technology
1 answer:
Viefleur [7K]3 years ago
6 0
Ooeration support system. OSS is IT for running a communications network.
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This operating system was used by individual computers and required users to type commands.
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Answer:

MS-DOS is your answer

Explanation:

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Text that is heavier or darker than other text in the document is considered _____.
kvv77 [185]

The text that is heavier or darker than other text in a document is considered  Bold.

Hope this helped!~

7 0
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A recipe for deducing the square root involves guessing a starting value for y. Without another recipe to be told how to pick a
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Answer:

TRUE

Explanation:

TRUE - A recipe for deducing the square root involves guessing a starting value for y. Without another recipe to be told how to pick a starting number, the computer cannot generate one on its own.

5 0
3 years ago
"running computer programs and their data are stored in ___"
Lesechka [4]

Solution:

Running computer programs and their data are stored in Rom.

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5 0
4 years ago
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Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
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