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agasfer [191]
3 years ago
13

construct a right-angled triangle ABC where angle A =90 degree , BC= 4.5cm and AC= 7cm. please ans fast........ Very urgent. Pls

don't give wrong answers

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0

Answer and Step-by-step explanation: The described right triangle is in the attachment.

As it is shown, AC is the hypotenuse and BC and AB are the sides, so use Pytagorean Theorem to find the unknown measure:

AC² = AB² + BC²

AB^{2} = AC^{2}-BC^{2}

AB =\sqrt{AC^{2}-BC^{2}}

AB =\sqrt{7^{2}-4.5^{2}}

AB =\sqrt{28.75}

AB = 5.4

Then, right triangle ABC measures:

AB = 5.4cm

BC = 4.5cm

AC = 7cm

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48,919 ÷ ? = 489.19<br> 489,190 ÷ 1,000 =?<br> 4,891,900 ÷ ? = 489.19<br> ? ÷ 100,000 = 489.19
musickatia [10]

Answer:

  • 100
  • 489.190
  • 10,000
  • 48,919,000

Step-by-step explanation:

Each factor of 10 in the divisor causes the decimal point to move 1 place to the left.

a) The decimal point has moved 2 places to the left. The divisor is 10^2 = 100.

b) The divisor is 10^3, so the decimal point will move 3 places to the left.

  489.190

c) The decimal point has moved 4 places to the left, so the divisor is 10^4 = 10,000.

d) The divisor is 10^5, so the decimal point in the quotient if 5 places to the left of where it is in the dividend. Moving the quotient's decimal point 5 places to the right gives ...

  48,919,000

_____

<em>Additional comment</em>

An exponent signifies repeated multiplication. Here, we're concerned with repeatedly multiplying (or dividing) by factors of 10. The exponent indicates the number of factors: 10·10 = 10^2 = 100. It also matches the number of zeros following the 1 in the product. 1000 = 10^3 has 3 zeros after the 1, for example.

3 0
2 years ago
Solve the following proportion for X
mixer [17]
Answer: 3.7 (to nearest tenth)

Working:
7/17 = x/9
63 = 17x
x = 63/17
x = 3.7 (to nearest tenth)
8 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
consider the following equations: -x-y=1 y=x+3 if the two equations are graphed, at what point do the lines representing the two
Oksana_A [137]

Answer:

(-2, 1)

Step-by-step explanation:

consider the following equations: -x-y=1 y=x+3

For the lines to intersect, the  values must be the same

-x-y=1

x + y = -1

y = -x - 1

Equating the y values

-x - 1 = x+ 3

-x-x = 3 + 1

-2x = 4

x = 4/-2

x = -2

Substitute x = -2 into y = x+3

y = -2 + 3

y = 1

Hence the required coordinate is (-2, 1)

7 0
2 years ago
Variable definition?
kkurt [141]
The number beside the letter . for example 6x, 6 would be the variable
5 0
3 years ago
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