Can someone help me with this math homework please!

Mathematics

1 answer:

mamaluj [8]2 years ago

4 0

Answer:

The rock hits the ground between 2 seconds and 2.5 seconds after it is dropped

Step-by-step explanation:

The given table is presented as follows;

$\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}$

Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.

You might be interested in

On a coordinate grid, point T is at (2, −4) and point S is at (2, 6). The distance (in units) between points T and S is ______.

-BARSIC- [3]

The answer is 10
This is because both points have the same x value, which is 2, which means the distance between them is a straight line. That means that we can simply find the distance between the y values, and -4 to 0 is 4 units, and 0 to 6 is 6 units, so 4 + 6 = 10.

I hope this helps!

6 0

2 years ago

Read 2 more answers

Divide x to the 1 half power divided by x to the 2 sevenths power.

juin [17]

$\frac{x^\frac{1}{2} }{x^\frac{2}{7}}$