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Radda [10]
3 years ago
11

If I have a mass of 40g and a volume of 20ml, then what is the density?

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer:

2g/mL^3

Step-by-step explanation:

To find density, we use mass/volume. 40g is the mass and 20mL is the volume. 40/20 is 2, therefore, 2g/mL^3

JulijaS [17]3 years ago
6 0
2Kg/m^3

Density= mass/volume
Density= 40/20
2
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From the table, the speed of Corinne is given by

speed=slope= \frac{2.5-1.25}{20-10} = \frac{1.25}{10} =0.125 \ miles / minute

From the graph, the speed of Aretha is given by

speed=slope= \frac{5.5-4.5}{20-10} = \frac{1}{10} =0.1 \ miles / minute

The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t

Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then

0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140

Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.
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Find the gratest common factor of 36 and 90
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Step-by-step explanation:

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Law of sines: 2.2 units 2.4 units 3.0 units 3.3 units
Arada [10]

Answer:

RS=2.4\ units  

Step-by-step explanation:

<em>The complete question is </em>

What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.

see the attached figure to better understand the problem

step 1

Find the measure of angle S

Applying the law of sines

\frac{QS}{sin(R)}=\frac{QR}{sin(S)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{2.4}{sin(S)}

Solve for sin(S)

sin(S)=\frac{sin(80^o)}{3.1}(2.4)

S=sin^{-1}[sin(80^o)}{3.1}(2.4)]

S=49.68^o

step 2

Find the measure of angle Q

Remember that the sum of the interior angles in any triangle mut b equal to 180 degrees

so

m\angle Q+m\angle R+m\angle S=180^o

substitute the given values

m\angle Q+80^o+49.68^o=180^o  

m\angle Q+129.68^o=180^o  

m\angle Q=180^o-129.68^o

m\angle Q=50.32^o

step 3

Find the length of segment RS

Applying the law of sines

\frac{QS}{sin(R)}=\frac{RS}{sin(Q)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{RS}{sin(50.32^o)}

RS=\frac{3.1}{sin(80^o)}{sin(50.32^o)}  

RS=2.4\ units          

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Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Nu
Tasya [4]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Answer:

a. Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. P(at least B) = 0.330

c. P(pass) = 0.855

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years.

He uses the following scale for grading.

Grade     Numerical Score      Probability

A                       4                            0.090

B                       3                            0.240

C                       2                            0.360

D                       1                            0.165

F                       0                            0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

The cumulative probability distribution is given by

Grade = F

P(X ≤ x) = 0.145

Grade = D

P(X ≤ x) = 0.145 + 0.165 = 0.310

Grade = C

P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670

Grade = B

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910

Grade = A

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1

Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

At least B means equal to B or greater than B grade.

P(at least B) = P(B) + P(A)

P(at least B) = 0.240 + 0.090

P(at least B) = 0.330

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Passing the course means getting a grade of A, B, C or D

P(pass) = P(A) + P(B) + P(C) + P(D)

P(pass) = 0.090 + 0.240 + 0.360 + 0.165

P(pass) = 0.855

Alternatively,

P(pass) = 1 - P(F)

P(pass) = 1 - 0.145

P(pass) = 0.855

4 0
3 years ago
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