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Svetlanka [38]
3 years ago
5

A square cake is cut into 16 equal parts. ben ears 7/16 of the cake. bell eats ¼ of the cake. what fraction of the cake is left?

what fraction of the cake is left?
Mathematics
1 answer:
Alexxx [7]3 years ago
4 0
Set both fraction to a common denominator
    
     7/16   and    4/16

now add them together

     7/16 + 4/16 = 11/16

now subtract that from a full cake
     
     16/16 - 11/16 = 5/16

there are 5/16 of the cake left

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Chicken costs $3.20 per pound, and beef costs $4.59 per pound. What is the exact cost of 3 pounds of chicken?
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$9.60

Step-by-step explanation:

3.20x3=9.60

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bulgar [2K]

Answer:

A) 26.563 miles in total

B) 1.977 more miles

Step-by-step explanation:

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2 years ago
Lily is a botanist who works for a garden that many tourists visit. The function f(s) = 2s + 30 represents the number of flowers
Vesnalui [34]

Answer:

  A. b(w) = 80w +30

  B. input: weeks; output: flowers that bloomed

  C. 2830

Step-by-step explanation:

<h3>Part A:</h3>

For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...

  b(w) = f(s(w)) = 2(40w) +30

  b(w) = 80w +30 . . . . . . blooms over w weeks

__

<h3>Part B:</h3>

The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.

The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.

Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).

__

<h3>Part C:</h3>

For 35 weeks, the number of flowers that bloomed is ...

  b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks

7 0
2 years ago
1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun
Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0
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