Answer: V = (12in - 2*x)*(8 in - 2*x)*x
Step-by-step explanation:
So we have a rectangular cardboard sheet, and we cut four squares of side length x in each corner so we can make a box.
Remember that for a box of length L, width W and height H, the volume is:
V = L*W*H
In this case, the length initially is 12 inches, but we remove (from each end) x inches of the length, then the length of the box will be:
L = 12 in - 2*x
For the width we have a similar case:
W = 8in - 2*x
And te height of the box will be equal to x, then:
H = x
This means that the volume is:
V = (12in - 2*x)*(8 in - 2*x)*x
Here we can see the connection between the cutout and the volume of the box
The asymptote of the function 
is y = 0.
The asymptote of the function 
is y = 0+4=4
Answer: y = 4
Step-by-step explanation:
it clearly consists of 2 rectangles and 1 triangle (as you tried correctly to point out by drawing the separating lines).
we only need to calculate all 3 areas and add them up for the total.
the area of a rectangle is
length × width
so, in our 2 cases we have
6 × 2 = 12 km²
5 × (3 + 2 + 3) = 5×8 = 40 km²
the area of a triangle is
baseline × height / 2
in case of a right-angled triangle the 2 sides enclosing the 90° angle can be used as baseline and height.
so, in our case
6 × (5 + 2 + (3 + 2 + 3 - 2)) / 2 = 6×(7 + 6)/2 = 3×13 = 39 km²
in total, the whole area is
12 + 40 + 39 = 91 km²
Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe
5w + 9z = 2z + 3w
Move terms with w to the left - subtract 3w from both sides
2w + 9z = 2z
Subtract 9z from both sides
2w = -7z
Divide both sides by 2
w = 
