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3 years ago

What function's domain consists of all real numbers greater than 3

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

The PLATO answer is f(x) = 3/x-3.

Reason: You can't divide by zero.

Hope this helps!

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Kelsey painted one-fourth of her bedroom in three-sevenths of an hour. At this rate, how long would it take her to paint the ent

malfutka [58]

12 Over seven of an hour

5 0

2 years ago

Can someone help me how do i do this i need an explination

Tanya [424]

Answer: From the figure attached,

Point X is the midpoint of line AC.

Since coordinates of the midpoint of the segment joining endpoints and is given by,

Therefore, coordinates of the point X will be, = (a, a)

From triangle AXB,

Length of AB = 2a

Length of AX =

Length of BX =

Length of AX = BX =

Therefore, triangle AXB is an isosceles triangle.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The following integers are listed in order from greatest to least. 10, 7, -3, -7

alexgriva [62]

Answer:

true

Step-by-step explanation:

negative numbers are smaller than positives and bigger negative numbers like -7 are lower than smaller negative numbers like -3

4 0

2 years ago

[(1/(3+x))-(1/3)] / x<br> Limit 0

Effectus [21]

First find a common denominator and combine the fractions in the numerator:

$\displaystyle\lim_{x\to0}\frac{\dfrac1{3+x}-\dfrac13}x=\lim_{x\to0}\frac{\dfrac3{3(3+x)}-\dfrac{3+x}{3(3+x)}}x=\lim_{x\to0}\frac{3-(3+x)}{3x(3+x)}$

Now simplify and cancel out all the terms that you can:

$\displaystyle\lim_{x\to0}\frac{3-3-x}{3x(3+x)}=-\frac13\lim_{x\to0}\frac1{3+x}$

Since the remaining expression is continuous as a function of $x$ , you can directly substitute to end up with

$\displaystyle-\frac13\lim_{x\to0}\frac1{3+x}=-\frac13\times\frac1{3+0}=-\frac19$

8 0

3 years ago

A bank loaned out $18,000, part of it at the rate of 9% per year and the rest at 19% per year. If the interest received in one

Galina-37 [17]

X * 0.09 + (18000-x)*0.19= 3000
x*(-0.1) + 3420 = 3000
x = -420/(-0.1)
x = 4200

The bank loaned out $4,200 at 9%

4 0

2 years ago