Answer:
I am a bit confused on what the question is asking. But 64*186= 11904 and if we were to round that number it would be 12000. 21*98=2058 and that number rounded is 2100 or just 2000. (hope this is right and helps :D)
Step-by-step explanation:
Answer: 
=====================================================
Reason:
Plot the points (0,0) and (r,s). You can place (r,s) anywhere you want.
Connect the two points mentioned and form a right triangle such that the segment from (0,0) to (r,s) is the hypotenuse of said right triangle.
The horizontal leg has a length of r-0 = r units, while the vertical leg will be 's' units.
Check out the diagram below.
We then apply the pythagorean theorem to say 
where h is the hypotenuse. Solving for h gets us 
. We only focus on the positive square root since a negative hypotenuse makes no sense.
Since we made the hypotenuse the segment with endpoints (r,s) and (0,0), this means the hypotenuse length and the distance are the same thing.
Therefore, the distance from (r,s) to (0,0) is 
As an alternative, you can use the distance formula to get the same answer. The distance formula is effectively the pythagorean theorem phrased a different way.
60 kilometers because it is 2 cm just multiply by 2
Question:
Charlotte has been working for her company for x years. Travis has been working for the same company exactly 3 years longer than Charlotte. What is the range of the relationship?
A- y>0
B- y>3
C. y<3
D. 0
Answer:
y > 3
Step-by-step explanation:
Number of years Charlotte has worked = x
Number of years Travis has worked = y. ie, y = 3+x
Let's assume the function reaches its lowest point at 3. There could also be a higher value for this function.
We now have:
f(x) = y > 3
Since Travis has been working for the same company exactly 3 years longer than Charlotte the range of the relationship is y>3
Answer:
3
Step-by-step explanation:
D(1 , 1) to D'(3, 3)
so x (1 x 3)= 3
y (1 x 3) = 3
SF = 3
D(1 , 5) to D'(3, 15)
so x (1 x 3)= 3
y (5 x 3 ) = 15
SF = 3
Same on coordinate points B to B' and C to C'
so SF = 3
