Answer:
3/7
Step-by-step explanation:
Opposite sides on a parallelogram are parallel, and parallel lines have the same slope, so once we find the slope of AB, we'll know the slope of CD. Point A is (-1,6) and point B is (6,9), so the slope of AB (and by extension, CD) is

I believe it is C because I counted the dots in the shaded region.
Hope it is correct :)
Answer:
6,000= y
2hrs= x
y=x
6,000y= 2=x
Step-by-step explanation:
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:


We can calculate the equation of
p by using its slope and its point P:
Answer:
The second answer, and possibly the first answer as also true.
She did run a test that would indicate its an unbalanced dice, but this wasn't tried out with a different person throwing the dice.
Step-by-step explanation:
This is because from the computer generator results we see 11 of the 25 values are estimating at 1/5 when we know dice are 1/6 and more than 1/2 show just under 1/5 which balances this to be 1/6
But there are 9/25 tests that showed values under 10 throws found a 6 in 9/25 events = 1/3 approx out of 1/10 of the throws, and 1/3 is still a higher value than 1/6 of the multiple throws so indicates 100 throws would not be enough to tell as we cannot possibly assume her results are comparable with a computer generator.As the computer generator completed 25 x 100 throws and have just compared only x10 in relation to 1/10 of the events of the generated computer. This showing 9 of the 25 (100) throw events in relation scores 1/3 of the results a 6. The answer is she would need to throw somewhere between 1000 and 3000 to compare to the computers results.