Answer:
<h3>
It can be concluded that this polynomial has a degree of 2, so the equation x²+x−12=0 has exactly two root</h3>
Step-by-step explanation:
Given the quadratic polynomial x²+x−12, the highest power in the quadratic polynomial gives its degree. The degree of this quadratic polynomial is therefore 2. <u>This means that the equation has exactly two solutions. </u>
Let us determine the nature of the roots by factorizing the quadratic polynomial and finding the roots.
x²+x−12 = 0
x²+4x-3x−12 = 0
= (x²+4x)-(3x−12) = 0
= x(x+4)-3(x+4) = 0
= (x-3)(x+4) = 0
x-3 = 0 and x+4 = 0
x = 3 and -4
This shows that the quadratic polynomial has <u>two real roots</u>
<u>It can be concluded that this polynomial has a degree of 2, so the equation x²+x−12=0 has exactly two roots</u>
The answer is C) 35.65 + 1.85x. Hope this helps...
Answer:
19.47
Step-by-step explanation:
Use the law of sines.
sin(90)/6 = sin(x)/2
Multiply both sides by 2
2 * sin(90)/6 = sin(x)
Use a calculator
0.33333 = sin(x)
sin^-1 0.3333 = 19.47
The answer to letter A is (x-y)² because if x=5 and y= -3 the problem would be (5-(-3))² and when you have -- that means you add. ik weird right. So basically that would be 8² which equals 64. Rather then the other one which was (x+y)² because again that would be (5+(-3))² but different because of the addition sign. so, that's asking what 5-3 is which is 2² which equals 4. Making (x-y)² bigger. I hope this helped
