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Readme [11.4K]
3 years ago
12

Which function describes this graph f(x)=4x+2 ??? Anybody please help ?

Mathematics
2 answers:
Korolek [52]3 years ago
8 0

Answer:

Step-by-step explanation:

f(x)=4x+2 is the equation of a straight line with slope 4 and y-intercept 2.

anygoal [31]3 years ago
5 0

Answer:

a line

Step-by-step explanation:

The graph would be a line since it is a linear equation. The line would have a y intercept at (0,2) and would have a slope of 4. I would look like a very steep mountain that gets higher as you move right.

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Help can you please solve this.
saveliy_v [14]

Answer:

x= -2

Step-by-step explanation:

7x+26+5x=2

7x+5x=12x

12x=2-26

12x= -24

(divide both sides by 12)

x= -2

5 0
3 years ago
Read 2 more answers
Identify the slope and intercept of the following linear equation.
IrinaK [193]

Answer:

3/7 is the slope and -5 is the y intercept

Step-by-step explanation:

y=3/7x-5

The equation is written in slope intercept form

y = mx+b where m is the slope and b is the y intercept

3/7 is the slope and -5 is the y intercept

3 0
3 years ago
Read 2 more answers
What is the slope of the line below?
RUDIKE [14]

Answer:

6/5

Step-by-step explanation:

I hope that it's a clear solution.

8 0
3 years ago
Read 2 more answers
What is the f of x over the g of x when f(x) = 6x3 − 19x2 + 16x − 4 and g(x) = x − 2? (2 points)
VikaD [51]
You're being asked to divide 6x^3 - 19x^2 + 16x - 4 by x - 2.

Try using synthetic division, if you know it:

     _______________
2  /   6    -19    16    -4
              12     -14    4
    --------------------------
        6     -7       2     0

6, -7 and 2 are the coefficients of the quotient.  The quotient (answer to this question) is

6x^2 - 7x + 2
4 0
3 years ago
The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate
Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}

Volume of cone =

V = \dfrac{1}{3}\pi r^2 h

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})

Putting values, we get,

\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0
3 years ago
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