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3 years ago

Number 4 Question D thank you

Mathematics

1 answer:

Zanzabum3 years ago

7 0

The English Channel is approximately -19 nautical miles (38000 yards) or 35 kilometres (35000 mtrs) - wide at its narrowest point (actually 18.2 nm from Shakespeare Beach, Dover to Cap Gris Nez, France). I hope this helps!

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Determine the kinetic energy of a 100-kg roller coaster car that is moving with a speed of 20.0/ms.

rjkz [21]

Answer:

The kinetic energy is 20,000\ J

Step-by-step explanation:

The kinetic energy of a body is defined as:

$k = \frac{1}{2}ms ^ 2$

Where m is the mass of the roller coaster car

s is the speed and k is the kinetic energy

We know that $s = 20\ m/s$

$m = 100\ kg$

Then the kinetic energy of the roller coaster car is:

$k = \frac{1}{2}(100)(20) ^ 2\\\\k = 50(20) ^ 2\\\\k = 50 * 400\\\\k = 20,000\ J$

3 0

3 years ago

Convert 7,200 in scientific notation

Nitella [24]

Answer:

7.2*10^3.

7,200 in scientific notation, is 7.2*10^3

8 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: