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alexandr402 [8]
4 years ago
12

Jack and Jill live 126 km apart. They want to leave their homes at the same time,

Mathematics
1 answer:
Digiron [165]4 years ago
7 0

Answer:

Both will leave their homes to meet on time at 9 am  

Step-by-step explanation:

Given as, Distance between Jack  and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides     = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill  =  (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So,     x = 18 × T

And  126 - x = 24 × T

Or,    126 - x =  24 × \frac{x}{18}

Or,    126 - x =  x × \frac{4}{3}

Or,    378 - 3x = 4x

Or,    378 = 7x

i.e x = \frac{378}{7} = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = \frac{x}{18} = \frac{54}{18}

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = \frac{72}{24} = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am   Answer

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Suppose f is a one-to-one function with f(2)=8 and f’(2)=4. What is the value of (f^-1)’(8)?
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Step-by-step explanation:

The tangent line to f(x) at x=2 goes through the point (2, 8) and has slope 4.

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=======================================

Problem 4

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