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3 years ago

Solve for X 1/5 X + 1/2 = 1

Mathematics

1 answer:

Alik [6]3 years ago

7 0

Answer:

X = 5/2

Step-by-step explanation:

I will assume that you meant (1/5)X + 1/2 = 1. The LCD is 10.

Multiplying both sides by 10, we get:

2X + 5 = 10, or 2X = 5, or X = 5/2

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During first semester the ratio of the number of students in art class to the number of students in gym class was 2:7. However t

elena-s [515]

5/4 = 75/g....cross multiply because this is a proportion
5g = 300
g = 300/5
g = 60
so in 2nd semester, there were 75 students in art class and 60 students in gym class....for a total of 135 students.

1st semester....ratio was 2:7...added = 9
art : 2/9(135) = 270/9 = 30 <=== art class had 30
gym: 7/9(135) = 945/9 = 105 <=== gym class had 105

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3 years ago

Gasoline is pumped at rate of 3 gallons per minute into a container that already has 4 gallons inside

maksim [4K]

Answer:

1 1/3 minutes

Step-by-step explanation:

Gasoline is pumped at rate of 3 gallons per minute into a container that already has 4 gallons inside

From the above question, we are to calculate the time at which the gasoline is pumped into the container

Hence:

Time = Number of gallons/Rate

Number of gallons = 4

Rate = 3 gallons per minutes

Hence:

Time = 4 gallons/3 gallon per minutes

Time = 1 1/3 minutes

The time at which the gasoline is pumped into the container is 1 1/3 minutes

8 0

3 years ago

What is the slope intercept form of the function that contains the point (6,2) and has a slope of 3?

skelet666 [1.2K]

You can plug in the numbers like 2=3(6) + b then rearrange for b so 2-18=b so the answer to your question is y=3x-16

4 0

3 years ago

Read 2 more answers

Eleven of the 25 people on the bus get off at the first stop. What percent best represents the portion of the bus that got off o

Degger [83]

Answer:

44%

Step-by-step explanation:

11 out of the 25 students got off the bus so we divide 11 by 25.

$\frac{11}{25} = .44$ .

$.44 = 44%$ %

6 0

3 years ago

Researchers would like to know the mean body temperature of runners at the completion of a marathon. They plan to take a random

sasho [114]

Answer:

They would know a and b.

a. The mean of this distribution, by the Central Limit Theorem, is the sample mean, and thus, the researches would know this after they took the sample.

b. Sample size is 100 > 30, and thus, by the Central Limit Theorem, they would know that the shape of the distribution is approximately normal.

c. To know the standard deviation of the sampling distribution of the sample mean, the researchers would have to know the population's standard deviation, which they can't get for the sample. So they would not know the standard deviation of the sampling distribution of the sample mean after they took the sample.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

a. The value of the mean of the sampling distribution of the sample mean.

The mean of this distribution, by the Central Limit Theorem, is the sample mean, and thus, the researches would know this after they took the sample.

b. The approximate shape of the sampling distribution of the sample mean.

Sample size is 100 > 30, and thus, by the Central Limit Theorem, they would know that the shape of the distribution is approximately normal.

c. The standard deviation of the sampling distribution of the sample mean.

To know the standard deviation of the sampling distribution of the sample mean, the researchers would have to know the population's standard deviation, which they can't get for the sample. So they would not know the standard deviation of the sampling distribution of the sample mean after they took the sample.

5 0

3 years ago