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melamori03 [73]
3 years ago
9

A sociologist develops a test to measure attitudes about public transportation, and 27 randomly selected subjects are given the

test. Their mean score is 76.2 and their standard deviation is 21.4. Construct the 95% confidence interval for the standard deviation, σ, of the scores of all subjects.a. 17.5 < σ < 27.8b. 17.2 < σ < 27.2c. 285.61 < σ <858.49d. 16.6 < σ < 28.6e. 16.9 < σ < 29.3
Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer: e. 16.9<\sigma<29.3

Step-by-step explanation:

As per given , we have

n= 27 , \overline{x}=76.2  , s=21.4

Critical value using Chi-square table:-

\chi^2_{\alpha/2, n-1}=\chi^2_{0.025, 26}=41.92317010\\\\ \chi^2_{1-\alpha/2, n-1}=\chi^2_{0.975, 26}=13.84390498

Confidence interval for standard deviation:

\sqrt{\dfrac{(n-1) s^2}{\chi^2_{\alpha/2, n-1}}}< \sigma

Hence, the 95% confidence interval for the standard deviation, σ, of the scores of all subjects : 16.9

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17) Sometimes true

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18) Always true

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19) Always true.

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20) Never true

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8 0
1 year ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
The odds of flipping a fair coin either heads or tails is 50%. The odds of rolling a six on a fair six sided die is 16.6% or 1 i
creativ13 [48]

Answer:

P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.

The final probability will be sum of the above given probabilities.

Hence P( sum is prime )= 73/216

8 0
3 years ago
Help me plz!!!!!!!!!!!!!
4vir4ik [10]
22 and 27 is the answer. what else do you need??
8 0
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Simplify: (14y+x) +22y=??
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Answer:

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Step-by-step explanation:

i did it and got a 100%

5 0
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