Question

What’s the equation of a line that passes through (-9,10) and y=3/2x - 3/2

Answer 1

Answer:

y = 3x/2 + 23 1/2

Or

y = 3x/2 + 47/2

Step-by-step explanation:

Find the slope

y = 3/2x - 3/2

Equation of a line

y = mx + c

m = 3/2

using a point slope form equation

Substitute the point into the equation

( -9 , 10)

y - y1 = m( x - x1)

x1 = -9

y1 = 10

y - 10 = 3/2( x - (-9)

y - 10 = 3/2( x + 9)

Open the bracket

y - 10 = (3x + 27)/2

y = ( 3x + 27)/2 + 10

LCM = 2

y = ( 3x + 27 + 20)/2

y = ( 3x + 47)/2

Separate to get the value of slope and intercept

y = 3x/2 + 47/2

y = 3x/2 + 23 1/2

The equation of the line is

y = 3x/2 + 23 1/2