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3 years ago

PLZ HELP ME (PICTURE OF PROBLEM)

Mathematics

1 answer:

Lyrx [107]3 years ago

6 0

AB = 7 1/2

BC = 2 1/4

DE = 1 1/4

AB = GH + EF + CD

AH + FG = DE + BC

The perimeter is AB + BC + CD + DE + EF + FG + GH + HA.

AB + BC + CD + DE + EF + FG + GH + HA =

= AB + BC + DE + AB + DE + BC =

= 2AB +2BC +2DE =

= 2 · 7 1/2 + 2 · 2 1/4 + 2 · 1 1/4 =

= 15 + 4 2/4 + 2 2/4 =

= 15 + 4 1/2 + 2 1/2 =

= 19 1/2 + 2 1/2 =

= 22 [m]

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The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

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f=11

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We are given that

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Score(x) frequency C.F

1 1 1

2 3 4

3 f 15(4+f=4+11)

4 13 28

5 4 32

$\sum f_i=1+3+f+13+4=21+f$

$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

$Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}$

Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

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