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ValentinkaMS [17]
2 years ago
8

(ii) During a sale, the price of a bag of rice was reduced from N25,000 to N20,000. What percent of decrease does this represent

? ​
Mathematics
2 answers:
torisob [31]2 years ago
6 0
Answer: 20%

Explanation:
We have to remember a percentage is something out of a total or original amount. In this case, the original price is 25,000.

Now we have to find out how much it decreased. 25,000 to 20,000 is a decrease of 5,000.

Now the percentage is the amount out of the total. This is 5,000 (decrease) out of 25,000 (original price)

5,000/25,000
5/25
20/100
.2 or 20%
OLga [1]2 years ago
3 0

Step-by-step explanation:

exactly.

maybe this helps even more : always identify what is supposed to be 100% and what would be 1% then (1/100 of 100%). and then you check how often 1% fits into the amount in question.

100% = 25000

1% = 100%/100 = 25000/100 = 250

the price decrease is 25000 - 20000 = 5000.

so, the percentage is

difference /1% = 5000/250 = 20%

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It's 7:18... Because you have to because 7 subtract 2:12 is 7, and half is 30 min...
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2 less than 3 times a number greater than 10. Write as inequality
vesna_86 [32]

Answer:

2<3x>10

Step-by-step explanation:

2<3x>10

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3 years ago
Solve for x.<br> Help ASAP please!!!
sattari [20]

Answer:

The value of x is 4

Step-by-step explanation:

In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then

∵ The length of one side of the right triangle = (x + 2)

∵ The length of the hypotenuse = x + 5

∴ (x + 2)² = x (x + 5)

∵ (x + 2)² = (x + 2)(x + 2)

∴ (x + 2)(x + 2) = x(x + 5)

→ Simplify the two sides

∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)

∴ x² + 2x + 2x + 4 = x² + 5x

→ Add the like terms in the left side

∴ x² + 4x + 4 = x² + 5x

→ Subtract x² from both sides

∵ x² - x² + 4x + 4 = x² - x² + 5x

∴ 4x + 4 = 5x

→ Subtract 4x from both sides

∴ 4x - 4x + 4 = 5x - 4x

∴ 4 = x

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3 0
3 years ago
Which fraction has a terminating decimal?<br> - 11/19<br> - 4/7<br> - 1/3<br> - 3/150
babunello [35]
<h3>Answer: D) 3/150</h3>

==========================================================

Explanation:

With the use of a calculator, we see that,

  • 11/19 = 0.57894736842106...., the decimals eventually repeat; but unfortunately my calculator ran out of room to show the repeating portion
  • 4/7 = 0.5714285714285714..., the block "571428" repeats forever
  • 1/3 = 0.333333.... the 3s go on forever
  • 3/150 = 0.02

So 3/150 converts to the terminating decimal 0.02

The word "terminate" means "stop". In the other decimal values, the decimal digits go on forever repeating the patterns mentioned.

----------------------

A non-calculator approach will have us simplify 3/150 into 1/50 after dividing both parts by the GCF 3. Then notice how 50 has the prime factorization of 2*5*5. The fact that the denominator 50 can be factored in terms of only 2's and 5's is enough evidence to conclude that the fraction converts to a terminating decimal.

If the denominator factors into some other primes, other than 2s and 5s, then we don't have a terminating decimal. So that's why 11/19, 4/7 and 1/3 convert to non-terminating decimals.

6 0
3 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
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