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3 years ago

3.) Find the domain and range for each of the following functions.

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Domain is x’s and range is y’s.

For a, the domain is -2<=x<1
For a, the range is 1<=y<2

For b, the domain is 1<=x<=2
For b, the range is -2<=y<=2

(The <= is the ones with a line under, meaning equal to, if that makes sense. So write with a line under rather than equal sign)
Hope this helps!

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Tanzania [10]

Answer: x= 54

Step-by-step explanation:mathhhhh

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2 years ago

Improper fracations

NemiM [27]

Answer:

64+77=141

Step-by-step explanation:

The whole number times the denominator plus the numerator. Then, add and do the same thing again with the other number and you get 64 and 77 then add and you get 141

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3 years ago

Describe and correct the error the student made when writing the equation of the line that passes through (-8,5)

pshichka [43]

Option D (The student should have used as the slope of the perpendicular line.) is correct.

Step-by-step explanation:

We need to identify the error that the student made in finding equation of the line that passes through (-8,5) and is perpendicular to y = 4x + 2

The slope of the required line would me -1/m because both lines are perpendicular.

So, slope of new line will be: -1/4

because the equation of slope-intercept form is: $y=mx+b$ where m is the slope

Now, for finding equation the student used point slope form i.e $y-y_1=m(x-x_1)$

where y_1 and x_1 are the points and m is the slope.

Putting values:

x_1=-8, y_1=5 and m=-1/4

$y-5=-\frac{1}{4}(x-(-8))\\y-5=-\frac{1}{4}(x+8)\\y-5=-\frac{1x}{4}-2\\y=-\frac{1x}{4}-2+5\\y=-\frac{1x}{4}+3$

This is the correct solution.

The student made error by using the wrong slope he used 2 instead of -1/4

in the step $y-5 = 2(x-(-8))$

So, Option D (The student should have used as the slope of the perpendicular line.) is correct.

Keywords: Equation of line using Slope

Learn more about Equation of line using Slope at:

#learnwithBrainly

3 0

2 years ago

Read 2 more answers

Determine the slope of the lines parallel and perpendicular to -4x+3y=11

andreev551 [17]

Answer:

parallel = 4/3

perpendicular =-3/4

Step-by-step explanation:

Solve for y

-4x+3y=11

Add 4x to each side

3y = 4x+11

Divide by 3

y = 4/3 x +11/3

This is in the form y = mx+b where m is the slope

m =4/3

The parallel line has the same slope

parallel slope is 4/3

The perpendicular line has a negative reciprocal slope

m = -(1 /4/3) = - 3/4

6 0

3 years ago

Read 2 more answers

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago