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3 years ago

15

3.) Find the domain and range for each of the following functions.

1 answer:

Delvig [45]3 years ago

6 0

Domain is x’s and range is y’s.

For a, the domain is -2<=x<1
For a, the range is 1<=y<2

For b, the domain is 1<=x<=2
For b, the range is -2<=y<=2

(The <= is the ones with a line under, meaning equal to, if that makes sense. So write with a line under rather than equal sign)
Hope this helps!

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Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

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3 years ago

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Answer:

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3 years ago

If y=0.9 when x=2.4, find y when x=6.4

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2 years ago

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Answer:

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Step-by-step explanation:

we know that

The surface area of a rectangular prism is given by the formula

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

Let

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W ---> the width of the prism

H ---> is the height of the prism

Let

$L=2\ ft\\W=3\ ft\\H=1\ ft$

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$B=LW=(2)(3)=6\ ft^2$

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therefore

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Answer:

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Step-by-step explanation:

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