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STatiana [176]
3 years ago
7

Which points on the wave are the trough and the crest?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

ok

trough is the y

Crest is W

I put a picture for help

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If a piece of ribbon is 5 and 1 over 2. Feet long, how long is it in inches? 33 inches 55 inches 60 inches 66 inches
galben [10]

Answer:The answeris 66 inches.


Step-by-step explanation:


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3 years ago
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Last month, when Joe took his puppy to the veterinarian, the puppy weighed 4.6 pounds. This month, the puppy weighed 5.98 pounds
Karo-lina-s [1.5K]
Percent increase : (new number - original number) / (original number)....then multiply that by 100 to get ur percent.

(5.98 - 4.6) / (4.6) = 1.38/4.6 = 0.3......0.3 x 100 = 30% <==
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3 years ago
Shelly is 3 years older than Michelle. 4 years ago the sum of their ages was 67. find the age of each person now
Murljashka [212]
If Shelly is 3 years older than Michael and There 67. Michael is 64 and Shelly is 67. Or Michael is 67 and Shelly is 70.

Hope I helped. Have a wonderful day
3 0
3 years ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
If 2x + 5 =8 ×, then 12x=
nadya68 [22]
<span>2x + 5 =8x
6x = 5
x = 5/6

12x = 12(5/6) = 10</span>
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