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topjm [15]
3 years ago
11

SCHOOL Half of the students in Max’s class volunteer at the local community center. Fifteen students do not volunteer. If there

are 12 boys in Max’s class, how many girls are in his class?
Mathematics
1 answer:
damaskus [11]3 years ago
6 0
18. 15 x 2 = 30, 30-12=18
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The second answer is right
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A triangle has an area of 56 square units. It's night is 14 units. What is the length of its base?
NNADVOKAT [17]

Answer:

8 units

Step-by-step explanation:

b(14)/2 = 56

14b = 112

b = 8 units

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Can someone pls pls pls help me Evaluate the expression 6.908 – g for g = 0.173.
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Answer:

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4 0
3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
I WILL MARK BRAINLIEST FOR CORRECT ANSWER :)
Ostrovityanka [42]

The answer to that question would be 14
4 0
3 years ago
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