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3 years ago

11

SCHOOL Half of the students in Max’s class volunteer at the local community center. Fifteen students do not volunteer. If there

are 12 boys in Max’s class, how many girls are in his class?

1 answer:

damaskus [11]3 years ago

6 0

18. 15 x 2 = 30, 30-12=18

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Sqrt (y^4 * y)
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3 years ago

Please can someone explain and help me I am giving away 14 points the question is in the image

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The area is 67.36 cm squared

Step-by-step explanation:

The height is 8.982. The base is 15. 8.982 * 15 = 134.73 / 2 = 67.36

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2 years ago

A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are

nikitadnepr [17]

Answer:

Area(A)=Area(C)= $9 in^{2}$

Area(B)= $13.2 in^{2}$

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)= $\frac{b*h}{2}$ = $\frac{6*3}{2}$ = $9 in^{2}$

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

$h=[tex]6*cos(30)=5.20in$ The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6= $31.2 in^{2}$

Area(B)=Area(rhomboid)-Area(A)-Area(C)= $31.2 in^{2}$ - $9 in^{2}$ - $9 in^{2}$ = $13.2 in^{2}$

3 0

2 years ago

A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He

Vitek1552 [10]

Answer:

Maximum area = 800 square feet.

Step-by-step explanation:

In the figure attached,

Rectangle is showing width = x ft and the side towards garage is not to be fenced.

Length of the fence has been given as 80 ft.

Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced

80 = x + x + y

80 = 2x + y

y = (80 - 2x)

Now area of the rectangle A = xy

Or function that represents the area of the rectangle is,

A(x) = x(80 - 2x)

A(x) = 80x - 2x²

To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

$A'(x)=\frac{d}{dx}(80x-2x^{2})$

= 80 - 4x

A'(x) = 80 - 4x = 0

4x = 80

x = $\frac{80}{4}$

x = 20

Therefore, for x = 20 ft area of the rectangular patio will be maximum.

A(20) = 80×(20) - 2×(20)²

= 1600 - 800

= 800 square feet

Maximum area of the patio is 800 square feet.

7 0

3 years ago