The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Let X= the number of tickets sold at $35 each
Let 350 -X = the number of tickets sold at $25 each
The number of tickets sold for each type will be computed as follows:
X(35)+(350-X)25=10250
35X+8750-25X=10250
10X=10250-8750
X=1500/10
X=150 the number of tickets sold at $35 each
350-150 the number of tickets sold at $25 each
To recheck:
150(35)+200(25)
5250+5000
10250
By pythagorean thoerm u can find
Hy^2=length^2+base^2
Answer:
300
Step-by-step explanation:
75 multiplied by 4 is 300
Remark
Please number your pairs of equations going from left to right. The pair on the extreme left is (1) and the pair on the extreme right is (5).
(1)
If you multiply to top member of the pair by 2, you will get the bottom equation of the pair. What that tells you is that there are many (infinite) numbers of solutions.
(y = 3x + 4) * 2 remove the brackets.
2y = 6x + 8 Exactly the same equation as the bottom one = infinite solutions.
(2)
If the slopes are the same (both are -1) and the y intercepts are different (0,-2) and (0,-6) then the lines are parallel (they never meet) and have no solutions.
(3)
If the slopes are different, there is one solution. (9 and 1) There is one solution.
(4)
Four gives 1 solution as well at 0,0. That is because the slopes are different.
(5)
trick question. the slopes are quite different. one is 0 and the other is undefined. They meet at one point.(-6,-3). I solution.
