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3 years ago

How are the answers to problems 6,8,12, and 14 similar?how are they different?

Mathematics

2 answers:

Tasya [4]3 years ago

8 0

Answer:

Step-by-step explanation:

Citrus2011 [14]3 years ago

7 0

Answer:

well it's been a long time so I really forgot I'm sorry

Step-by-step explanation:

You might be interested in

How is the sum expressed in sigma notation? 1/64+1/16+1/4 + 1 + 4

shusha [124]

9514 1404 393

Answer:

sum = ∑[n=1,5] 4^(n-4)

Step-by-step explanation:

First of all, you need to be able to describe the n-th term.

Here, we have ...

term #: 1, 2, 3, 4, 5

value: 4^-3, 4^-2, 4^-1, 4^0, 4^1

That is, the exponent of 4 is 4 less than the term number. So, the n-th term is 4^(n-4). The sum of the 5 terms shown is then ...

$\displaystyle sum=\sum_{n=1}^5{4^{n-4}}$

5 0

3 years ago

A party host is making identical party bags for guests using 44 bottles of bubbles, 89 stickers, and 55 pencils. What is the gre

Umnica [9.8K]

Answer: 11 party bags with 1 sticker leftover

Each bag contains 4 bubbles, 8 stickers, and 5 pencils.

Step-by-step explanation:

Find the GCF of 44 (bubbles), 89 (stickers), and 55 (pencils)

44: 2 x 2 x 11

89: prime so choose 88 with 1 leftover

88: 2 x 2 x 2 x 11

55: 5 x 11

GCF = 11

Disregard the GCF to see how many of that item should go in each bag.

Bubbles: 2 x 2

Stickers: 2 x 2 x 2

Pencils: 5

7 0

3 years ago

Evaluate Combination (6,6)

andrew11 [14]

Answer:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

$6C6$

And the general formula for combination is given by:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

8 0

3 years ago

A football team plays in a large stadium. With a ticket price of $17, the average attendance at recent games has been 50,000.

Verizon [17]

Answer:

a. N(x) = 50000 - 200x

b. R(x) = (50000-200x)(17+x)

Step-by-step explanation:

a. Given,

The the original price of each ticket = $ 17,

Also, the average attendance = 50,000

Let x be the number of times the original price of each ticket is increased by $ 1,

Also, for each $1 increase in the ticket price, attendance decreases by 200,

Thus, decrements in the attendance = 200x,

If N(x) represents the new average attendance,

Then,

N(x) = 50000 - 200x

Which is the required function,

b. Now,

Revenue = average attendance × price of each ticket

R(x) = N(x) × ( 17 + x )

⇒ R(x) = (50000-200x)(17+x)

Which is the required function.

3 0

3 years ago

Bobby has a bag containing 2 sizes of marbles. The big ones weigh 10 g and the small ones weigh 3 g. If there are three times as

Vikentia [17]

Answer:

There are 19 big marbles

Step-by-step explanation:

10a + 3b = 209

a = 3b

3b = 3b

10a + a = 209

11a = 209

a = 209/11

a = 19

8 0

3 years ago