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Lana71 [14]
3 years ago
15

If each of the following questions were asked to a group of second graders, which question would NOT be a statistical question?

A. What time do you wake up in the morning? B. How tall are you? C. How many brothers and sisters do you have? D. What grade are you in?​
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer:

d

Step-by-step explanation:

just makes sense bc they're all in 2nd grade

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Given the recursive formula for a geometric sequence find the common ratio, the first four terms, and the explicit formula.
Dahasolnce [82]
Since a(n)=-3(a(n-1)) the common ratio is -3, and a(1)=-3 so

a(n)=-3(-3^(n-1)) so the first four terms are:

-3, 9, -27, 81
4 0
3 years ago
What is 5 times 7h equal.does it equal 35h
RSB [31]
Yeah the answer is 35 because if you multiply 5x7 it will give u 35 for an answer
3 0
3 years ago
Find the total surface area of a cylinder if r=2 and h=8
Ghella [55]

Answer:

100.5

Step-by-step explanation:

22/7*2^2*8

=22/7*4*8

=22/7*32

=100.5

5 0
3 years ago
leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a
Georgia [21]
The answer is x =  \frac{-7+ \sqrt{193} }{4}.

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is A = \frac{a*h}{2}, where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula A =  \frac{a*h}{2}:
36 =  \frac{(2x+3)(3x+6)}{2}
⇒ 36*2=6 x^{2} +12x+9x+18
72=6 x^{2} +21x+18

Let's both sides divide by 3:
24=2 x^{2} +7x+6
⇒ 2 x^{2} +7x-18=0

This is the quadratic formula (a x^{2} +bx+c=0) for which
x =  \frac{-b+\sqrt{b^{2} -4ac} }{2a} or
<span>x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}.
</span>We will use only <span>x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}, because the length cannot have negative value.</span>


<span>From the equation 2 x^{2} +7x-18=0, we know that
</span>a = 2
b = 7
c = -18

Thus, <span> x = \frac{-7+ \sqrt{193} }{4}:
</span>x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}

4 0
3 years ago
Help me with math please
xenn [34]
Yes I agree with that
7 0
3 years ago
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