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3 years ago

15

If each of the following questions were asked to a group of second graders, which question would NOT be a statistical question?

A. What time do you wake up in the morning? B. How tall are you? C. How many brothers and sisters do you have? D. What grade are you in?

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer:

d

Step-by-step explanation:

just makes sense bc they're all in 2nd grade

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The graph of f(x) = x2 was transformed to create the graph of g(x) = (x − 7.5)2. Which of these describes this transformation?

QveST [7]

Answer:

A. A horizontal shift to the right 7.5 units

Step-by-step explanation:

Replacing x with x-7.5 shifts the graph 7.5 units to the <em>right</em>.

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In general, g(x) = f(x-h)+k will shift h units right and k units up. In this problem there is no vertical shift.

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3 years ago

In a small Library there are five non-fiction books for every nine fiction book there are 130 Non-fiction books how many fiction

vova2212 [387]

Answer:

For 130 non-fiction books, the number of fiction books can be from 270 to 278.

Step-by-step explanation:

Given that, there are 5 non-fiction books for every 9 fiction books.

Observe that, if the number of fiction books is less than 9, than there will be no no-fiction books.

So, there are 5 non-fiction books for every 9 to (9+8) fiction books

So, by elementary method, there will be 5n non-fiction books for every 9n+8 fiction books, where n is a natural number.

Or, if the number of non-fiction books is 5n, then the number of fiction books will be ranging from 9n to (9n+8).

For, 150 non-fiction books, 5n=150 or n=150/5=30.

Hence, the number of fiction books can be from 9n to (9n+8).

=9x30 to (9x30+8)

=270 to 278.

Hence, for 130 non-fiction books, the number of fiction books can be from 270 to 278.

6 0

3 years ago

Anna is saving to buy a new cell phone. Her mother is helping Anna by contributing money each month. What is the ratio between t

Dmitry [639]

Answer:

Option D. 3:1, $120

Step-by-step explanation:

The complete question in the attached figure

Part 1) What is the ratio between the amount of money contributed by Anna and the amount contributed by her mother?

Let

x -----> the amount of money contributed by Anna

y ----> the amount of money contributed by her mother

we know that

Looking at the table

The value of x is equal to $x=\$30+\$60+\$90+\$120=\$300$

The value of y is equal to $y=\$10+\$20+\$30+\$40=\$100$

Find the ratio x/y

substitute the values

$\frac{x}{y}=\frac{300}{100}=\frac{3}{1}$

Part 2) What was the total amount saved in April?

we know that

To find out the total amount saved in April, adds Mon's contribution in April plus Anna's contribution in April

so

$(\$30+\$90)=\$120$

3 0

3 years ago

Read 2 more answers

Please help? What is the tangent ratio of angle B?

bearhunter [10]

Answer:

Step-by-step explanation:

The tangent equation = side opposite angle / side beside angle

which in this case is $tan\alpha =AC/ BC$

which is the third choice

Hope that helps!

5 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago