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Dennis_Churaev [7]
3 years ago
9

28/6 as a whole or mixed number and in simplified form

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

Answer:

4 2/3

Step-by-step explanation:


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The table represents f(x), and the graph represents g(x). Which statements about the functions are true for the interval [4, 10]
nikitadnepr [17]
The rate of change for f(x) for the interval [4,10] will be approximated by:
=(Δ y-axis)/(Δ x-axis)
=(0.4-1)/(10-4)
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Rate of change for g(x) for interval [4,10]
=(1-2.5)/(10-4)
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from the above guesstimate we can deduce that average rate of change for f(x) is less than that of g(x). Thus the answer will be:
 <span>B) The average rate of change of f(x) is less than the average rate of change of g(x).</span>
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Are all diagonals also lines of symmetry in a polygon?
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Give the digits in the ones place and the hundredths place.<br> 74.12
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The digit in the ones place is 4 and the digit in the 100ths place is 2

Step-by-step explanation:

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3 years ago
I’ll give 10 points if you help!
GuDViN [60]

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Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)
sashaice [31]

Answer:

f(x) = x^3  -sinx +Cx+D

Step-by-step explanation:

Given that:

f ''(x)= 6x +sinx

We are given the 2nd derivative of a function f(x) and we need to find f(x) from that.

We will have to integrate it twice to find the value of f(x).

Let us have a look at the basic formula of integration that we will use in the solution:

1.\ \int {(a\pm b)} \, dx =\int {a} \, dx + \int {b} \, dx \\2.\ \int {x^n} \, dx = \dfrac{x^{n+1}}{n+1}+C\\3.\ \int {sinx} \, dx = -cosx+C\\4.\ \int {cosx} \, dx = sinx+C

\int\ {f''(x)} \, dx =\int\ {(6x +sinx)} \, dx \\\Rightarrow \int\ {6x} \, dx  + \int\ {sinx} \, dx \\\\\Rightarrow 6\dfrac{x^2}{2} -cosx +C\\\Rightarrow 3{x^2} -cosx +C\\\Rightarrow f'(x)=3{x^2} -cosx +C\\

Now, integrating it again to find f(x):

f(x) =\int {f'(x)} \, dx =\int{(3{x^2} -cosx +C)} \, dx \\\Rightarrow \int{3{x^2}} \, dx  -\int{cosx} \, dx  +\int{C} \, dx\\\Rightarrow 3\times \dfrac{x^3}{3}  -sinx +Cx+D\\\Rightarrow x^3  -sinx +Cx+D\\\\\therefore f(x) = x^3  -sinx +Cx+D

5 0
4 years ago
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