Check the picture below.
something worth noticing
so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.
Answer:
Step-by-step explanation:
Given polynomial is,
6y² - 7y - 2
Fro the zeros of the given polynomial,
6y² - 7y - 2 = 0
6y² - 4y - 3y - 2 = 0
2y(3y - 2) - 1(3y - 2) = 0
(2y - 1)(3y - 2) = 0
(2y - 1) = 0
y =
(3y - 2) = 0
y =
Therefore, zeros of this polynomial are m = and n =
If a polynomial has zeros as and
then the zeros will be
and 2.
Polynomial will be,
=
=
=