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1 year ago

Select the correct answer.

Mathematics

1 answer:

Pani-rosa [81]1 year ago

8 0

Answer:

Step-by-step explanation:

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A line with a slope of 3 passes through the point (-1, 2).

Rom4ik [11]

Answer:

y - 2 = 3(x + 1)

y - 2 = 3x + 3

y = 3x + 5

Step-by-step explanation:

8 0

2 years ago

1/2 -(-1/3 + 2/5) = what is the answer ? thank you for helpings means alot to me

taurus [48]

The answer would come out to 13/30

7 0

2 years ago

Hi! I know this is not the correct way to ask a question, but may someone explain how to do the Division Property of Equality an

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

So the division property states that if both sides of an equation are equal and whenever you divide both sides of that equation by the same number they should stay equal. Example

12=12 right? so if I divide both 12 and 12 by 3 I should get 3=3

We use this to solve for variable such as x

So new example lets take

5x=25

Since both sides are equal I can divide by the same number and should get an equal number right? So lets divide by 5 on both sides. 5x divided by 5 equals x and 25 divided by 5 equals 5 so my new equation is

x equals 5 or x=5.

If I plug my x=5 back into the equation they should be equal so lets see...

5(5)=25

25=25

And it checks out :)

3 0

2 years ago

Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only)

Eduardwww [97]

Given:

The figure of a right triangle. $PO=12,m\angle O=y^\circ$ and perpendicular = 12.

To find:

The measure of angle y.

Solution:

In a right angle triangle,

$\sin\theta=\dfrac{Perpendicular}{Hypotenuse}$

In the given right angle triangle,

$\sin y^\circ=\dfrac{7}{12}$

$y^\circ=\sin ^{-1}\dfrac{7}{12}$

$y^\circ=35.685335^\circ$

$y^\circ\approx 35.69^\circ$

Therefore, the measure of angle y is $y^\circ =35.69^\circ$ .

7 0

2 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

2 years ago