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asambeis [7]
2 years ago
9

Evaluate the log by thinking “3 to what power is 1/9 so log3(1/9) =

Mathematics
1 answer:
Vlad [161]2 years ago
8 0

Answer:-2

Step-by-step explanation:

Log3(1/9)

Log(1/9) ➗ Log3

Log(1/3^2) ➗ Log3

Log3^(-2) ➗ Log3

-2Log3 ➗ Log3

-2(Log3 ➗ Log3)

-2

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D -e/3d + e= e, for d​
navik [9.2K]

Answer:

\large\boxed{d=\dfrac{e^2+e}{1-3e}}

Step-by-step explanation:

\dfrac{d-e}{3d+e}=e\\\\\dfrac{d-e}{3d+e}=\dfrac{e}{1}\qquad\text{cross multiply}\\\\(1)(d-e)=(e)(3d+e)\qquad\text{use the distributive property}\\\\d-e=3de+e^2\qquad\text{add}\ e\ \text{to both sides}\\\\d=3de+e+e^2\qquad\text{subtract}\ 3de\ \text{from both sides}\\\\d-3de=e^2+e\qquad\text{distribute}\\\\d(1-3e)=e^2+e\qquad\text{divide both sides by}\ (1-3e)\\\\d=\dfrac{e^2+e}{1-3e}

8 0
3 years ago
The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in
garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

7 0
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