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3 years ago

Which relation is a function?

Mathematics

1 answer:

Degger [83]3 years ago

5 0

Answer: Id say C.

Step-by-step explanation: The other two can't possibly be a function.

<h2><em>Mark as brainliest if im correct please</em></h2>

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HELPPP!!!! Will mark BRAINLIEST!!!!

Svetach [21]

Answer:

Step-by-step explanation:

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8 0

2 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

PLEASE HELP ME I NEED TO PASS THIS TEST

Evgesh-ka [11]

Answer:

2a^2 + 2a - 11

Step-by-step explanation:

(2a^2-5) +(-6+2a)

substitute

6 0

3 years ago

Plz answer me will mark as brainliest read full question

Musya8 [376]

Answer:83 -->17-->103-->43-->7-->1

Have a good day

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3 years ago

Two friends, Parker and David, took summer jobs. The graph below represents David's earnings in dollars and cents, yy, for worki

siniylev [52]

Answer:

WORK For Exercises 44 and 45, use the information below and in the graph. Andrea works in a restaurant and is paid every two weeks. If Andrea earns $ 6.50 an hour, illustrate the Distributive Property by writing two expressions representing Andrea's pay last week.

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2 years ago