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Marta_Voda [28]
3 years ago
14

use the information on justines test paper to express the part of the 80 test questions she got correct as a fraction,percent an

d decimal she got 68 correct
Mathematics
1 answer:
kompoz [17]3 years ago
5 0
<span>  80 divide by 68 is 1.17647058824</span>
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Volume of a sphere with a radius of 3
Musya8 [376]

Answer:

113.1

Step-by-step explanation:

6 0
3 years ago
Your gas tank holds 13.5 gallons of gas your fuel gauge shows that your tank is one quarter full your car gets an average of 25
Gekata [30.6K]

Answer:

  The brother is likely wrong.

Step-by-step explanation:

The range of the vehicle with a full tank is ...

  (13.5 gal/tank)(25 mi/gal) = 337.5 mi/tank

You have 1/4 tank, so your range is ...

  (337.5 mi/tank)(1/4 tank) = 84.375 mi

If you make the 85 mile distance, it will be because you achieved gas mileage better than average and/or your gas gauge gives you some cushion.

Unit analysis says you do not have the necessary range.

7 0
3 years ago
Help your boy out please
ELEN [110]

Answer:

the answer is A x=4

Step-by-step explanation:

when we plug x=4 in each of the function we get the value 2

when we plug x=3 we get an undefined value

when we plug x= 2 and x=1 we get complexed values so

the answer is x=4

f(4)=1/(4-3)+1

=1/1+1

=1+1

= 2

g(4)=2√(4-3)

=2(√1)

=2(1)

=2

4 0
3 years ago
SOME ONE HELP ME I REALLY NEED A SOLUTION FOR THIS PROBLEM WITH A CLEAR EXPLANATION
Sergio [31]

I'm going to answer this question using logic.  Let x be Jenny's favorite number.  We are going to square root this number, \sqrt{x} and then multiply it by \sqrt{2}.

This product needs to be an integer.  How is that obtainable? To be an integer, we need to get rid of the nasty \sqrt{2} part.  The only way I can think of to get rid of it, is to multiply it by \sqrt{2}, because \sqrt{2} *\sqrt{2} = 2.  Thus we have some conditions we need to fulfill when choosing Jenny's favorite number.

When we take the square root of Jenny's favorite number, x, it must contain a perfect square and a 2 in its prime factorization.  For example, 8 works because 8 = 2 x 2 x 2, or 2² x 2.  

You notice 8 is made up of a perfect square multiplied by 2.  So when we take the square root of 8, we get:

\sqrt{8} = \sqrt{2^{2}*2 } = \sqrt{ 2^{2} }*\sqrt{2} = \sqrt{4} *\sqrt{2} = 2*\sqrt{2}

So 8 is the same thing as 2\sqrt{2}

So when we multiply this by \sqrt{2}, we will get an integer! So as long as Jenny's favorite number consists of a perfect square and two in its prime factorization, we will have an integer!

So possible choices are: 2,8,18.

Why does 18 work? Because \sqrt{18} = \sqrt{9}* \sqrt{2} = 3\sqrt{2}

When we multiply this by \sqrt{2}, we get 6, which is an integer.

b) Suppose instead of multiplying by \sqrt{2}, we divided by \sqrt{2}. Is the resulting quotient still an integer?

YES, because we can get rid of the \sqrt{2} part by dividing by \sqrt{2} as well.  This leaves only the "perfect square" part left in our square root, and obviously a perfect square is an integer when we square root it.

I hope that made sense! (⌐■_■)

3 0
3 years ago
Consider the following formula.
icang [17]

Answer:

= (z-y)/(a-b)

Step-by-step explanation:

ax-bx + y =z

ax-bx =z -y

x (a-b) = -y

x = (z-y) / (a-b)

6 0
3 years ago
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